magnitude of the force‚ d is the object’s displacement‚ and is the angle between the direction of the force and the displacement . Solving simple problems requires substituting values into this equation. More complex problems‚ such as those involving friction‚ often require using Newton’s second law to determine forces. Example: An Eskimo returning from a successful fishing trip pulls a sled loaded with salmon. The total mass of the sled and salmon is 50.0 kg‚ and the Eskimo exerts a force of 120
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especially fluid mechanics‚ and for his pioneering work in probability andstatistics. Bernoulli’s work is still studied at length by many schools of science throughout the world. In Physics :- He is the earliest writer who attempted to formulate a kinetic theory of gases‚ and he applied the idea to explain Boyle’s law.[2] He worked with Euler on elasticity and the development of the Euler-Bernoulli beam equation.[9] Bernoulli’s principle is of critical use inaerodynamics.[4] Daniel Bernoulli‚ an
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Roller Coasters The main energy transfers that happens as a “car” travels along the track from the start of the ride to the end. 1. The main energy transfers are between gravitational potential energy (GPE) and kinetic energy (KE)‚ and the eventual decrease of mechanical energy as it transforms into thermal energy. Roller coasters often start as a chain and motor exercises a force on the car to lift it up to the top of a very tall hill. At this height‚ GPE is at its highest‚ as we can see
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coefficient of friction is 0.25 for the first part of the trip and 0.55 for the second. If the child always pulls horizontally‚ how much work does the child do on the box? WTotal=F1Δd1+F2Δd2 F1=FN=μmg Δd1=10 m m=20 kg μ=0.25 W1=(0.25)(20)(9.8)(10)
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is … positive negative zero 5 Work: Example Fapp FN Direction of motion Friction‚ Ffr FW Negative work reduces the kinetic energy of a system. Friction ALWAYS does negative work Gravity does zero work ONLY if the motion is parallel to the/along a horizontal surface 6 Work-Kinetic energy relation Wtot = !KE = K f " K i Due to APPLIED FORCES (e.g. elastic force (following Hooke’s law)‚ friction‚ gravity‚ tension‚ normal force‚ etc.) For a particle in Linear motion 1 2
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twice the mass of the other‚ experience the same force for the same time. What is their difference in momentum? What is their difference in kinetic energy? 2. A 12 g bullet is fired horizontally into a 96 g wooden block initially at rest on a horizontal surface. After impact‚ the block slides 7.5 m before coming to rest. If the coefficient of kinetic friction between block and surface is 0.60‚ what was the speed of the bullet immediately before impact? You have to use the conservation of the total
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will convert energy into kinetic energy as the mouse-trap car begins to move. But there is friction and in order to overcome friction you have to do more work. Friction converts energy into heat and sound which takes away energy from your motion‚ causing the car to stop as its energy is turned into other forms. When designing a mousetrap car‚ there are two variables that truly determine the overall performance: friction and energy. If my mousetrap car has too much friction‚ the energy in the spring
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streamline g = acceleration due to gravity h = height of the fluid p = pressure along the streamline ρ = density of the fluid These assumptions must be met for the equation to apply: • Inviscid flow − viscosity (internal friction) = 0 • Steady flow • Incompressible flow − ρ = constant along a streamline. Density may vary from streamline to streamline‚ however. • Generally‚ the equation applies along a streamline. For constant-density potential flow‚ it applies
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24‚ 2009 Kinetic Friction Experiment #13 Joe Solution E00123456 Partner - Jane Answers PHY 221 Lab Instructor – Chuck Borener Thursday‚ 11 AM – 1 PM Lecture Instructor – Dr. Jacobs Abstract In this experiment‚ we test factors which effect friction. We pulled a wood block across a surface to determine whether the surface area of the block or the type of surface effects friction. We found that the surface area of the block did not change the coefficient of kinetic friction‚ while the types
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the system’s change in energy. Here‚ the object starts with kinetic energy [KE = (mv^2)/2] and friction brings it to rest by doing an equivalent amount of work. Work is‚ in this case‚ the product of the force of friction and the distance the object slides while coming to rest. Therefore‚ the distance the object slides is directly proportional to the kinetic energy of the object‚ and inversely proportional to the force of friction‚ i.e. d = (mv^2)/(2F). The 2-kg mass is half the mass of the
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