Sohal‚ S 04/05/11 (HLT-362 V) Applied Statistics for Healthcare Professionals Exercise 18 Q1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between ( - 53.68‚ 64.64)‚where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places. Answer: Mean of weight relative to ideal = 5.48 and Standard Deviation (σ) = 22.93. Calculation: (x bar) 1.96(σ) 5.48± 1.96(22.93) 5.48 - 1.96(22.93)
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WEEK FOUR DQ1 Explain the importance of random sampling. What problems/limitations could prevent a truly random sampling and how can they be prevented? Probability sampling‚ also known as random sampling‚ requires that every member of the study population have an equal opportunity to be chosen as a study subject. For each member of the population to have an equal opportunity to be chosen‚ the sampling method must select members randomly. Probability sampling allows every facet of the study population
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EXERCISE IN STATISTICS Below are hypothetical data. (1) Organize them in bivariate tables to answer the problems below. Determine the statistics to use for each. 1. Are sex and occupation associated? 2. Are age and income correlated? 3. Are educational attainment and sex associated? 4. Are civil status and occupation associated? 5. Are occupation and income related N>E> you may use data transformation (from interval data to nominal data) Respondent No. Age Sex Civil Status Educational attainment
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not = 440 Statistic 4.9 With 98% confidence Lower limit 3.05348411 Upper limit 24.7249703 With 98% confidence we cannot reject Ho since the statistic is inside the acceptance zone b) Check the same hypothesis with 95% confidence. With 95% confidence Lower limit 3.81574825 Upper limit 21.9200493 With 95% confidence we cannot reject Ho since the statistic is inside
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1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (-53.68‚64.64)‚ Where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places. X =5.48‚ SD = 22.93 5.48 – 1.96(22.93) = AND 5.48 + 1.96(22.93) = 5.48 – 44.9428 = AND 5.48 + 44.9428 = -39.4628 AND 50.422 (-39.46‚ 50.42) 2. Which of the following values from Table 1 tells us about variability of the scores in a distribution
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1. What are the advantages and disadvantages of grid and free-flow layout arrangements? | ADVANTAGES | DISADVANTAGES | GRID LAYOUT | Easy to locate merchandiseCost-efficientEasily accessible for customersCustomer familiarityEase in cleaningSimplified securityPossibility of self-service | Limited browsingLimited creativity in décor (Plain and uninteresting)Stimulation of rushed shopping behavior | FREE-FLOW LAYOUT | Incread creativity in decor items to display?sed impulse buyingVisual appealFlexibility
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HLT362V Week 1 Homework EX#16 Answers for EXERCISE 16 page 122 (Questions 1- 4 are optional)• Mean and Standard Deviation Exercise 16: Mean and Standard Deviation 1. The researchers analyzed the data they collected as though it were at what level of measurement? a. Nominal b. Ordinal c. Interval/ratio d. Experimental Answer: c. The researchers analyzed the data as though it were at the interval/ratio level since they calculated means (the measure of central tendency that is appropriate
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□ EXERCISE 16 Questions to be Graded 1. The researchers analyzed the data they collected as though it were at what level of measurement? d. Experimental 2. What was the mean posttest empowerment score for the control group? The mean posttest empowerment score for the control group was 97.12 3. Compare the mean baseline and posttest depression scores of the experimental group. Was this an expected finding? Provide a rationale for your answer. The mean baseline depression score of
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Class: _Statistics____________Date: □ EXERCISE 16 Questions to be Graded 1. The researchers analyzed the data they collected as though it were at what level of measurement? d. Experimental 2. What was the mean posttest empowerment score for the control group? The mean posttest empowerment score was 97.12 3. Compare the mean baseline and posttest depression scores of the experimental group. Was this an expected finding? Provide a rationale for your answer. The mean baseline depression score
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EXERCISE 36 6. Can ANOVA be used to test proposed relationships or predicted correlations between variables in a single group? Provide rationale for your answer. ANOVA cannot be used to test proposed relationships or predicted correlations between variables in a single group because it is designed to test for correlations and interactions amongst groups‚ i.e. in the test group of patients with OA you are testing the correlations between those who do not use GI and PMR and those that do. Although
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