Sohal‚ S 04/05/11 (HLT-362 V) Applied Statistics for Healthcare Professionals Exercise 18 Q1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between ( - 53.68‚ 64.64)‚where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places. Answer: Mean of weight relative to ideal = 5.48 and Standard Deviation (σ) = 22.93. Calculation: (x bar) 1.96(σ) 5.48± 1.96(22.93) 5.48 - 1.96(22.93)
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are the assumptions for conducting a t-test for dependent groups in a study? Which of these assumptions do you think were met by this study? Answer: “The distribution of scores is normal or approximately normally distributed‚ the dependent variable(s) is (are) measured at interval or ratio levels‚ the groups examined for differences are dependent based on matching or subjects serving as their own control‚ and the differences between the paired scores are independent” are the assumptions for the t-test
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MAKE THE CHOICES WE DO? -If we all did these 15 things we would have a mortality rate that is half of what it is now -What is choice? Free Will Fate? Fun Hedonism (Hedonist choose pleasure) Control- people will want to exercise more if they feel a sense of control in the type of exercise they do Ex. HIV- if taken care of properly with medications aids patients can live a normal life span -Mother believed she didn’t need medication to cure her disease because of this guy on the Internet. -Medication could
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HLT362V Week 1 Homework EX#16 Answers for EXERCISE 16 page 122 (Questions 1- 4 are optional)• Mean and Standard Deviation Exercise 16: Mean and Standard Deviation 1. The researchers analyzed the data they collected as though it were at what level of measurement? a. Nominal b. Ordinal c. Interval/ratio d. Experimental Answer: c. The researchers analyzed the data as though it were at the interval/ratio level since they calculated means (the measure of central tendency that is appropriate
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ANSWERS TO EXERCISE 23 Question 1 The r value for the relationship between Hamstring strength index 60o and the Shuttle run test is -0.149. This r value shows a weak correlation between the two variables‚ as it is less than the 0.3 threshold for significance. Therefore‚ the r value is not significant. Question 2 Between r=1.00 and r=-1.00‚ there is no difference in terms of strength. Both values are on the extreme ends of the spectrum and signify the maximum significance within the r value scale. A
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Class: _Statistics____________Date: □ EXERCISE 16 Questions to be Graded 1. The researchers analyzed the data they collected as though it were at what level of measurement? d. Experimental 2. What was the mean posttest empowerment score for the control group? The mean posttest empowerment score was 97.12 3. Compare the mean baseline and posttest depression scores of the experimental group. Was this an expected finding? Provide a rationale for your answer. The mean baseline depression score
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□ EXERCISE 16 Questions to be Graded 1. The researchers analyzed the data they collected as though it were at what level of measurement? d. Experimental 2. What was the mean posttest empowerment score for the control group? The mean posttest empowerment score for the control group was 97.12 3. Compare the mean baseline and posttest depression scores of the experimental group. Was this an expected finding? Provide a rationale for your answer. The mean baseline depression score of
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“If you can’t explain it simply‚ you don’t understand it well enough.” Albert Einstein. Welcome to Pearson. We have a simple mission: to help people make more of their lives through learning. We’re the world’s leading learning company‚ but we believe that companies‚ like people‚ are Always Learning. That’s because there’s always room for a bit more understanding. (video) 1844 S. Pearson and Son is established as a small building firm in the north of England. 1935 Allen Lane publishes the
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EXERCISE 36 6. Can ANOVA be used to test proposed relationships or predicted correlations between variables in a single group? Provide rationale for your answer. ANOVA cannot be used to test proposed relationships or predicted correlations between variables in a single group because it is designed to test for correlations and interactions amongst groups‚ i.e. in the test group of patients with OA you are testing the correlations between those who do not use GI and PMR and those that do. Although
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standard deviation were used to describe the length of labor. These were appropriate since mean and standard deviation can be calculated on an interval level of measurement. 3. Range could also be used to describe the length of labor since this statistic can be used on interval data with no natural zero point. 4. The distribution of scores was similar for the experimental and control groups for length of labor. The experimental group had a mean of 14.63 hours and the control group had a mean of
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