Solution to Case Problem Specialty Toys 10/24/2012 I. Introduction: The Specialty Toys Company faces a challenge of deciding how many units of a new toy should be purchased to meet anticipated sales demand. If too few are purchased‚ sales will be lost; if too many are purchased‚ profits will be reduced because of low prices realized in clearance sales. Here‚ I will help to analyze an appropriate order quantity for the company. II. Data Analysis: 1. 20‚0 00 .025 10‚0 00 30
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Case Problem: Specialty Toys Specialty Toys‚ Inc.‚ sells a variety of new and innovative children’s toys. Management learned that the preholiday season is the best time to introduce a new toy‚ because many families use this time to look for new ideas for December holiday gifts. When Specialty discovers a new toy with good market potential‚ it chooses an October market entry date. In order to get toys in its stores by October‚ Specialty places one-time orders with its manufacturers in June or July
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be the demand for the toy. Then X follows normal distribution with mean μ = 20000 and standard deviation σ. Then P(10000 < X < 30000) = 0.95 P( X < 20000)=0.5 P(10000 < X < 20000) = 0.475 P( X < 10000)=0.025 NORM.S.INV(0.025)=-1.96 NORM.S.INV(0.975)=1.96 Z-score of 10000 =-1.96 Z-score of 30000=1.96 σ = (30000-20000)/1.96 =10000/1.96 = 5102 Standard Deviation of 5102 The graph above shows the distribution for the demand for the Weather Teddy Bear using Specialty Toys’ forecasts based off of
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of stockout will be 0.2177 At 28‚000 the probability of stockout will be 0.0582 3. Compute the projected profit for the order quantities suggested by the management team under three scenarios: worst case in which sales = 10‚000 units‚ most likely case in which sales = 20‚000 units and best case in which sales = 30‚000 units: Order Quantity: 15‚000 were cost price is $16‚ selling price $24 & after holiday selling price $5 |Unit Sales |Profit | |10‚000
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18. Based on a simple random sample of one hundred an analyst estimates the average hourly wage earned by workers in a city to be $30 and computes the margin of error to be $5. Can we conclude from this that most workers there earn between $25 and $35 per hour? Is the right interpretation for the margin of error? 23. Polls showed the two main candidates in the 2004 presidential election were nearly tied on the day before the election. To predict the winner a newspaper would like to have a poll
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1. Problem 1-8 Golf Specialties Company Name: Golf Specialties Products: Head covers‚ embroidered golf towels‚ umbrellas Popular Product: Head cover in the shape of a tiger Main Market: European countries Current Production Details: |Item |Tiger Head | |Per week Production |500 | |Unit Cost (variable + fixed cost)
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Interval Problem Answers AP Statistics Quiz A – Chapter – Key A statistics professor asked her students whether or not they were registered to vote. In a sample of 50 of her students (randomly sampled from her 700 students)‚ 35 said they were registered to vote. 1. Find a 95% confidence interval for the true proportion of the professor’s students who were registered to vote. (Make sure to check any necessary conditions and to state a conclusion in the context of the problem.) We have
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Final Examination Name: Course: Date: Final Examination in Statistics (M.A.Ed./M.A.N.) 1.The scores of 15 masteral students in Statistics were 80‚85‚78‚90‚91‚98‚95‚98‚95‚74‚71‚72‚98‚99‚and 87. Find the measures of central tendency‚ the range‚ the variance‚ and the standard deviation. 2. In the performance evaluation of teachers‚ if the dean’s evaluation is given a weight of 5‚ self-evaluation is 2‚ peer’s evaluation is 2‚ and student’s evaluation is 1 and the teacher’s
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GMB 713 PROBLEM SET NO. 2 PROBLEM SOLVING: Solve the following problems. Show all pertinent solutions. 1. A car battery dealer is trying to determine which of the brands of car battery he is selling has a longer life span. He conducted an investigation by interview his customers and was able to get the following results: Brand X Brand Y Mean life span 4.5 years 4.9 years Standard deviation
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Ch11 case Golf 1. is mean driving distances of current balls is mean driving distances of new balls is mean driving distances of sampled current balls is mean driving distances of sampled new balls Use the test statistics and normal distribution table to get p-value. If p-value is smaller than‚ then we reject H0‚ which means the mean driving distances of current balls and new balls are different. 2. From the t distribution table we find that p-value is between 0.05 and 0
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