Bromocyclohexane This reacted in 10 seconds because bromocyclohexane is secondary bromine‚ and has steric strain‚ since it is a cyclic compound. The bigger steric in a molecule‚ the harder it is for the nucleophile to attack the leaving group (-Br) from the opposite sides‚ therefore‚ SN2 reaction is slower than SN1 for bromocyclohexane Bromocyclopentane This reacted instantly because bromocyclopentane is secondary bromine‚ and have bigger steric strain than bromocyclohexane‚ since it is a cyclic compound
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bath to keep the reaction under control‚ and then sulfuric acid was added to the cold mixture. The sulfuric acid allowed for the metal in this case sodium to dissociate from the bromine atom allowing it to have a negative charge. The positive cation left on the carbon that lost the alcohol will be replaced by the bromine ion‚ creating 1-bromobutane. The lab students had to understand the basic separation techniques to conduct this lab safe and effectively. They had to setup a simple distillation
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Radial and angular functions‚ hydrogen like wave functions‚ quantum numbers and their importance Chemical Bonding: Valence bond theory‚ Hybridization‚ VB theory as applied to ClF3‚ BrF5‚ Ni(CO)4‚XeF2‚ Dipole moment‚ Molecular orbital theory. Stereochemistry of carbon compounds: Stereo isomerism‚ Stereo isomers: enantiomers‚ diastereomers - Conformational and Configurational isomerismConformational‚ Enantiomers‚ Optical activity asymmetric and dissymmetric molecules‚ General Principles of Inorganic
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percent by mass of aluminum in Al2O3 is approximately 1) 18.9 3) 47.1 2) 35.4 4) 52.9 What is the approximate percent composition by mass of CaBr2 (formula mass = 200)? 1) 20% calcium and 80% bromine 2) 25% calcium and 75% bromine 3) 30% calcium and 70% bromine 4) 35% calcium and 65% bromine What is the empirical formula for C3H6? 1) CH 2) CH2 3) CH3 4) CH6 Which represents both an empirical and a molecular formula? 1) P2O5 2) N2O4 3) C3H6 4) C6H12O6 The number of atoms in 2
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variation of ozone results from the slow The ozone layer can be depleted by free radical catalysts‚ including nitric oxide (NO)‚ nitrous oxide (N2O)‚ hydroxyl (OH)‚ atomic chlorine (Cl)‚ and atomic bromine (Br). While there are natural sources for all of these species‚ the concentrations of chlorine and bromine have increased markedly in recent years due to the release of large quantities of man-made organohalogen compounds‚ especially chlorofluorocarbons (CFCs) and bromofluorocarbons.[4] These highly
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insoluble in alcohol‚ ether and acetone (organic solvents). 2.3 Melting Point 3. Chemical Properties of Tannins Expected Actual a). Ferric chloride Brownish green (+) Brownish green b). Gelatin Formation of precipitate (+) Green precipitate c). Bromine Brownish orange (+)
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conjugation which will stabilise the molecule. The mechanism for this step is unlikely to go via a simple elimination as for an elimination the eliminated products must be trans to each other for facile leaving. As the bromine is equatorial in both the chair and the boat conformation the bromine is trans with neither of the hydrogens which shows this type of elimination is unlikely to occur. The other possibility is that the acidic hydrogen that is removed in the first step is not H4‚ but H2. This
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begins to break (this is the transition state). The reaction is complete when a covalent bond has formed between the nucleophile and the carbon and the halogen has been removed as a halide ion. This process is accompanied with an inversion of stereochemistry at the targeted carbon center. In this experiment‚ our nucleophile is 1-methylimidazole and we will use it to attack 1-bromobutane (our alkyl halide) to form 1butyl-3-methylimidazolium bromide. We will refer to this molecule as [C4−mim]Br
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distilled water. Rinse with tap water and then with the acid. Rinse with the alkali. The labels fell off two bottles each containing a colourless solution‚ one of which was sodium carbonate solution and the other was sodium chloride solution. The addition of which solution to a sample from each bottle would most readily enable the bottles to be correctly relabelled? A B C D ammonia hydrochloric acid lead(II) nitrate sodium hydroxide © UCLES 2011 5070/11/O/N/11 3 3 Oxygen was prepared from
Free Oxygen Oxide Chlorine
Chapters 2.8-2.10: alcohols‚ halogenoalkanes‚ mechanisms and spectra Consolidation questions 1. Give the names of the two primary alcohols with the molecular formula C4H10O. butan-1-ol 2-methyl propan-1-ol 2. Write the equation‚ using state symbols‚ for the reaction of ethanol with sodium. CH3CH2OH(l) + Na(s) CH3CH2O-Na+(alc) + ½ H2(g) 3. Name the organic product above. Sodium ethoxide 4. Give the names and structural formulae for the two possible products
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