Experiment #8: Limiting Reactant Abstract In chemical reactions‚ the significance of knowing the limiting reactant is high. In order to increase the percent yield of product‚ increasing the limiting reactant‚ possibly‚ is the most effective. In this experiment we were able to calculate limiting reactants from the reaction of CaCl2. 2H2O + K2C2O4.H2O(aq). As a group‚ we obtained our salt mixture of calcium chloride and potassium oxalate‚ and weighed the mixture. We were able to make an aqueous
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something + 2Fe+2 Equation 2: 8H+ + 5Fe+2 + MnO4- --> 5Fe+3 + Mn+2 + 4H2O Equation 3: 6H+ + 2MnO4- + 5H2C2O4 --> 2Mn+2 + 10CO2 + 8H2O Conclusion: Therefore the concluded reaction would be: NH3OH+ + 2Fe+3 --> N2O + 2Fe+2 This was obtained by using stoichiometry half reactions the product of that reaction was determined to be N2O. Some systematic errors could be if the wrong molarity was determined for the permanganate because then that would though off the calculations for the Fe+2 and the rest of the
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Name: Brian James|Date:3/10/13| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: 73426| Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6_g Mass of weighing dish and Na2CO3 .72_g Net mass of the Na2CO3 .12_g Step 6: Mass of filter paper
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combining the elements‚ instead of having it naturally do so‚ made a significantly fully more bright color. In Theophilus’s “recipe” for vermillion‚ it is stated that there should be far more sulfur than a stiochiometric reaction should require. Stoichiometry
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Title: Stoichiometry of a Precipitation Reaction Purpose: The purpose is to predict the amount of precipitation using stoichiometry. Another purpose is to measure and calculate percentage yield. Procedure: 1. Weigh out 1.0g of CaCl2*2H2O and put it into a 100mL beaker. 2. Add 25mL of distilled water and stir. 3. Using stoichiometry to determine how much Na2CO3 is needed for a full reaction. 4. Weigh the calculated amount and put it in a small paper cup. Add 25mL distilled water and stir
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LAB REPORT 7 – STOICHIOMETRY OF A PRECIPITATION REACTION No credit will be given for this lab report if the Data section is not completely filled out. NOTE: This experiment may take several days to complete. OBJECTIVE 1. Predict the amount of product produced in a precipitation reaction using stoichiometry 2. Accurately measure the reactants and products of the reaction 3. Determine the actual and theoretical yield 4. Calculate percent yield PROCEDURE Please complete
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.6Name: Danielle Hall|Date: 10.15.2012| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: | Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6___g Mass of weighing dish and Na2CO3 __0.72__g Net mass of the Na2CO3 ___0.12_g Step 6: Mass of filter paper
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Investigation 3 Determine the Limiting Reagent Chemistry Investigation 3 Limiting Reagents Aim: To determine the limiting reagent in a reaction. Hypothesis: if the number of moles of the solutions added together equals the stoichiometry ratio in the balanced equation‚ then we would not expect a limiting reagent in the reaction. Independent variable: The number of moles of the reactants Dependent Variable: The limiting reagent Constant Variable: The volume of reactants added Equipment:
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Stoichiometry of a Precipitation Reaction Purpose: The purpose of this lab is to calculate the theoretical‚ actual‚ and percent yield of the product from a precipitation reaction. Also‚ to learn concepts of solubility and the formation of a precipitate. Procedure: Weigh out your 1.0g of CaCl2-2H20 and put it into the 100mL beaker‚ Add your 25mL of distilled water and stir to form the calcium chloride solution. Next‚ use stoichiometry to determine how much Na2CO3 and put it into a small
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F3.3 – LIMITING FACTORS • a factor that causes popn growth to decrease • two basic types: 1. density-independent factors 2. density-dependent factors 1. Density-independent factors • an abiotic event that affects all popn’s in the same way‚ regardless of popn density • e.g. fires‚ earthquakes‚ storms‚ temperature extremes… 2. Density-dependent Factors • a biotic interaction that varies in its effect on popn size‚ depending on the density of the popn involved • have greater impact on denser popn’s
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