IB CHEMISTRY Stoichiometry Lab Data Collection and Processing Item | Mass | Small beaker (100 mL) | 47.0 grams | Large beaker (150 mL) | 82.4 grams | Mass of filter paper | 0.50 grams | Mass of coffee filter | 1.00 gram | 150mL beaker + 20mL water + lead nitrate solution | 96.1 grams | 100mL beaker + 20mL water + sodium carbonate solution | 64.2 grams | Watch glass | 32.2 grams | Precipitate + filter paper + coffee filter | 2.20 grams | Precipitate + 150mL + coffee filter
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Copper-Iron Stoichiometry Lab Report 10/3/12 Abstract: The lab performed required the use of quantitative and analytical analysis along with limiting reagent analysis. The reaction of Copper (II) Sulfate‚ CuSO4‚ mass of 7.0015g with 2.0095g Fe or iron powder produced a solid precipitate of copper while the solution remained the blue color. Through this the appropriate reaction had to be determined out of the two possibilities. Through the use of a vacuum filtration system the mass of Cu was
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Chemistry 1: PROBLEM SET SY 2012/2013 CLASS #: _______________ NAME_________________________________________ SECTION: ______________________ Stoichiometry II - Mole Calculations/ Limiting and Excess Reagent – Lecture Notes 1. Given the balanced equation N2(g) + 3H2(g) 2NH3(g) How many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen? 2. Given the equation: SiO2 + HF SiF4 + H2O a. Calculate the number of moles HF that would completely react with 2.5 moles of
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Name: Brian James|Date:3/10/13| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: 73426| Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6_g Mass of weighing dish and Na2CO3 .72_g Net mass of the Na2CO3 .12_g Step 6: Mass of filter paper
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moles-stoichiometry-practice-problems Now you’re ready to use what you know about conversion factors to solve some stoichiometric problems in chemistry. Almost all stoichiometric problems can be solved in just four simple steps: 1.Balance the equation. 2.Convert units of a given substance to moles. 3.Using the mole ratio‚ calculate the moles of substance yielded by the reaction. 4.Convert moles of wanted substance to desired units. These "simple" steps probably look complicated at first
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Title: Stoichiometry of a Precipitation Reaction Purpose: The purpose is to predict the amount of precipitation using stoichiometry. Another purpose is to measure and calculate percentage yield. Procedure: 1. Weigh out 1.0g of CaCl2*2H2O and put it into a 100mL beaker. 2. Add 25mL of distilled water and stir. 3. Using stoichiometry to determine how much Na2CO3 is needed for a full reaction. 4. Weigh the calculated amount and put it in a small paper cup. Add 25mL distilled water and stir
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LAB REPORT 7 – STOICHIOMETRY OF A PRECIPITATION REACTION No credit will be given for this lab report if the Data section is not completely filled out. NOTE: This experiment may take several days to complete. OBJECTIVE 1. Predict the amount of product produced in a precipitation reaction using stoichiometry 2. Accurately measure the reactants and products of the reaction 3. Determine the actual and theoretical yield 4. Calculate percent yield PROCEDURE Please complete
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.6Name: Danielle Hall|Date: 10.15.2012| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: | Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6___g Mass of weighing dish and Na2CO3 __0.72__g Net mass of the Na2CO3 ___0.12_g Step 6: Mass of filter paper
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Chemistry Lab Report Stoichiometry Design Experiment Percentage Yield of Calcium Carbonate and HCl I. Background Information When marble chips and hydrochloric acid are added together‚ they form sodium chloride‚ water‚ and carbon dioxide. This reaction can be displayed by the balanced equation below; CaCO3 (s) + HCl (l) NaCl(s) + H2O(l) + CO2 (g) As the carbon dioxide is formed‚ it will leave the open beaker as a gas. This will result in a loss of mass. The mass change can then be
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Stoichiometry of a Precipitation Reaction Purpose: The purpose of this lab is to calculate the theoretical‚ actual‚ and percent yield of the product from a precipitation reaction. Also‚ to learn concepts of solubility and the formation of a precipitate. Procedure: Weigh out your 1.0g of CaCl2-2H20 and put it into the 100mL beaker‚ Add your 25mL of distilled water and stir to form the calcium chloride solution. Next‚ use stoichiometry to determine how much Na2CO3 and put it into a small
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