Section 3 BS 8110-1:1997 3.5.5.2 Shear stresses The design shear stress v at any cross-section should be calculated from equation 21: V v = -----bd equation 21 In no case should v exceed 0.8Æfcu or 5 N/mm2‚ whichever is the lesser‚ whatever shear reinforcement is provided. 3.5.5.3 Shear reinforcement Recommendations for shear reinforcement in solid slabs are given in Table 3.16. 3.5.6 Shear in solid slabs under concentrated loads The provisions of 3.7.7 may be applied. 3.5.7 Deflection Deflections
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transmits 150 kW‚ what is the maximum shear stress in the shaft? (b) If the allowable shear stress is 30 MPa‚ what is the maximum power that can be transmitted? Figure Q6. SOLUTION: Drive shaft for a truck ------------------------------------------------- Q7. A tubular shaft being designed for use on a construction site must transmit 120 kW at 1.75 Hz. The inside diameter of the shaft is to be one-half of the outside diameter. If the allowable shear stress in the shaft is 45 MPa‚ what
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ABSTRACT This paper compares the deformation modulus of rock measured from laboratory and field tests which were carried out as part of the site investigation works for a major project in Irbid‚ Jordan. Laboratory resonant column and torsional shear tests were performed at different confining pressures whereas ultrasonic velocity tests were conducted on unconfined rock specimens. In addition‚ empirical relationships were used for estimating the rock mass modulus employing the results of the
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internal loadings in a member. To introduce the concepts of normal and shear stress. To analyse and design members subject to axial load and direct shear. To define normal and shear strain‚ and show how they can be determined for various types of problems. Copyright © 2011 Pearson Education South Asia Pte Ltd In-Class Activities • • • • • • • • Reading Quiz Applications Normal Stress Shear Stress Normal Strain Shear Strain Cartesian Strain Components Concept Quiz Copyright © 2011 Pearson
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Qatar University Mechanical and Industrial Engineering Department MECH 223 Solid Mechanics L51 Spring 2013 Term Project Group no. (6) Course Instructor: Dr. Mohammed Al-Qaradawi T.A: Eng. Salim Mohandes Group members: Amal Bsaisu 201002072 Nada Mamdouh 201105374 Nazha Ghadban 201104186 Ola Al-Masri 201103017 Samar Nasr 201000137 Due Date: 3-6-2013 Abstract: In this project we were asked
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book is to describe both the basic hydrodynamics and the basic sediment transport mechanism. The reader’s background should be a basic course in wave theory and fluid mechanics. Chapter 1 deals with fundamentals in fluid mechanics with emphasis on bed shear stress by currents‚ while Chapter 3 discusses wave boundary layer theory. They are both written with a view to sediment transport. Sediment transport in rivers‚ cross-shore and longshore are dealt with in Chapters 2‚ 4 and 5‚ respectively. It is not
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Chapter 1 General concepts of stress and strain • The end of the chapter‚ the students should be able to: – Find internal forces of a body – Calculate the average normal stress and average shear stress of a body subject to axial forces and shear forces respectively – Calculate the normal strain from a body`s deformation – Understand and be able to apply the relationship between stress and strain. – Locate and identify material characteristics associated with a tensile test stress-strain diagram
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BEAM DESIGN DESIGN LOAD 1. Calculate factored point load (P.43‚ Table 4.2) 2. Calculate max shear‚ V for all axis 3. Calculate max moment‚ M for all axis SECTION PROPERTIES 1. Write down all section properties (Section table) SECTION CLASSIFICATION 1. Obtain design strength‚ py (P.32‚ Table 3.2) 2. Calculate ε 3. 4. 5. Classify flange (P.66-68‚ Table 7.1-7.2‚ 7.3) Classify web (P.66-68‚ Table 7.1-7.2‚ 7.3) Conclude classification (選最差) 275 py LOCAL PLATE BUCKLING (有 COMPRESSION 先計)(FOR CLASS
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Failure of Knuckle Joint in Tractor with Trolley‚ Design and Make Better Knuckle Joint A SEMINAR REPORT Submitted by SORATHIYA GHANSHYAM D. In fulfilment for the award of the degree of BACHELOR OF ENGINEERING in MECHANICAL ENGINEERING GOVERNMENT ENGINEERING COLLEGE‚ BHAVNAGAR‚ GUJARAT TECHNOLOGICAL UNIVERSITY‚ AHMEDABAD December‚ 2011 GOVERNMENT ENGINEERING COLLEGE‚ BHAVNAGAR‚ MECHANICAL ENGINEERING 2011 CERTIFICATE Date: 13-12-2011 This is to certify
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however small they may be. Conversely‚ it follows If a fluid is at rest‚ there can be no shearing forces acting‚ and‚ therefore‚ all forces in the fluid must be perpendicular to the planes upon which they act. Shear Stress in a Moving Fluid There is no shear stress in a fluid at rest; shear stresses are developed when the fluid is in motion. If the particles of the fluid move relative to each other so that they have different velocities‚ they cause the original shape of the fluid to become distorted
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