equilibrium condition exists and hence the deformation stops. • These internal forces maintain the externally applied forces in equilibrium. Contd… • Stress = internal resisting force / resisting cross sectional area = R/ A • The internal force resisting the deformation per unit area is called as stress or intensity of stress. • SI unit for stress: N/m2 • Also designated as a pascal (Pa) Pa = N/m2 Contd… • gigapascal‚ 1GPa = 1×109 N/m2 = 1×103 MPa= 1×103 N/mm2 • kilopascal‚ 1kPa = 1000
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common in areas with steep slopes‚ where trees have been cut down‚ in droughts when crops and other vegetation grow poorly and in rural areas which are overpopulated. Nepal‚ in the Himalayan Mountains‚ has severe problems caused by increased population density and steep slopes. Soil erosion can be reduced by building terraces on hillsides‚ irrigation schemes to overcome droughts‚ planting more trees to bind the soil together and make wind breaks‚ and using fertilizers in overpopulated areas to make
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government level involving larger area and heavy investment. (a) Small Measures-These include afforestation‚ regularised land strip cultivation or contour farming or terrace farming in hilly areas‚ use of stubble mulch system‚ increasing cohesiveness of the soils through artificial manures and fertilisers‚ gully plugging‚ restricting over grazing and shifting cultivation‚ erecting shelter belts and wind breaks to check wind velocity and wind erosion in arid and semi-arid areas‚ Fixing of sand dunes by
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Specialized Areas Chitkara Principles: Functional Programming • • • • • • • Broad knowledge & Literature overview Ability to cater to any eventualities Logical flow Interdepartmental harmony Complete range of specialty services Rule of adjacency Special design requirements Ultimately will create a design brief for the Architect Chitkara Functional Programming • After thrust areas analysis‚ one needs to identify functional areas under following categories • Core Areas (Directly Related
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Chapter Test Area Results of the quiz. 1. Find the area of ΔABC. The figure is not drawn to scale. * CORRECT: 23.14 cm2 2. Find the area of a parallelogram with vertices at P(–8‚ –3)‚ Q (–7‚ 3)‚ R(–9‚ 3)‚ and S(–10‚ –3). * CORRECT: 12 square units 3. A slide that is inches by inches is projected onto a screen that is 3 feet by 7 feet‚ filling the screen. What will be the ratio of the area of the slide to its image on the screen? * CORRECT: 1 : 12‚544 4. Find the area of the triangle
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Homework 1 Instructions In this homework‚ you will design a program to perform the following task: Calculate the usable area in square feet of house. Assume that the house has a maximum of four rooms‚ and that each room is rectangular. There are 4 components of your submission including: Program Description- A detailed‚ clear description of the program you are building. Analysis- Demonstrates your thought process and steps used to analyze the problem. Be sure to include the required
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032 | Average: | 0.032 | Table 2: Values for measuring the radius of capillary Temperature | 30 degrees Celsius | Density @ 30 degrees Celsius | 995.67 kg m-3 | Acceleration due to gravity | 9.8 m s2 | Height of water | 0.032 m | Surface tension of water@ 30 degrees Celsius | 7.118 X 10-2 N m | Radius of capillary tube | 4.5592825 X 10-4 m | Table 3: Values for the height of n-butanol solutions in capillary tube Temperature | Trial | 0.1 M | 0.2 M | 0.4 M | 0.6 M | 0.8 M |
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The factors that would cause the lung to collapse are elastic recoil and high surface tension. And the factors that prevent the lungs from collapse are negative intrapulmonary pressure and surfactant. During expiration : volume increase and pressure decrease During inspiration : volume decrease and pressure increase The role of surfactant is to decrease surface tension by more than 40 times. And it’s effect on surface tension is to prevent them from PO2 in alveolar : 104 PO2 in venous blood
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investigate the factors that affect the resistance in a conductor. The main factors that affect the resistance in a conductor are: · Length · Temperature · Cross sectional area · Material · Magnetism The factor that we are going to change is the cross sectional area. Hypothesis: I think that the higher the cross sectional area‚ the lower the resistance in the conductor will be. This is because the Resistance in a metal conductor happens because as the electrons move through the material (once
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Mathematics 6 I.Objectives: At the end of 60 minute period‚100% of the pupils with 75% proficiency level should be able to: A. Solve for the area of rectangle. B. Appreciate the ways of solving area of a rectangle. C. Write solution in finding the area of a rectangle. II. Learning Content Skill: Solving for the area of rectangle Reference: BEC PELC III 1.3 Materials: Charts‚Flash cards‚ruler Value: Appreciation III.Learning Experience A.Preparatory Activities
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