Performance Task in GEOMETRY * Computation of the surface area‚ amount and type of needed material and the volume of the package. Volume V= L x H x W = (23 cm) (4 cm) (12cm) = (276) (4) = 1 104 cm Area A= L x W = (23cm) (12cm) = 276cm Surface Area A= 2(Lh) + 2(Lw) + 2(Wh) / 2( lh + lw + wh) = 2(23*4) + 2(23*12) + 2(12*4) = 2(92) + 2(276) + 2(48)
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capacity. ____________________________________________________________ _________ 4. How does a shaping process differ from a surface processing operation? Answer. A shaping process changes the geometry of the work material (machining or forging). A surface processing operation does not alter the geometry‚ but instead alters the properties and/or appearance of the surface of the
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The factors that would cause the lung to collapse are elastic recoil and high surface tension. And the factors that prevent the lungs from collapse are negative intrapulmonary pressure and surfactant. During expiration : volume increase and pressure decrease During inspiration : volume decrease and pressure increase The role of surfactant is to decrease surface tension by more than 40 times. And it’s effect on surface tension is to prevent them from PO2 in alveolar : 104 PO2 in venous blood
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WIN8 TABLET SWEDISH MARKET STUDIES Unicorns Pamela Cominetti 61127 Sherry Wu 61138 Mario Harkmaa 61141 Mikael Fors 61123 Zhifan Yu 61150 Table of Contents Introduction ...................................................................................................................................... 2 Part I – Current Market Situation and Product Unique Selling Points ............................................ 2 Purchasing Drivers..............................................
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Super-hydrophobic surfaces‚ as well as‚ low adhesion and friction are desirable for various industrial applications. Hydrophobic (water-repellent) surfaces can be constructed either by using low surface energy materials or by chemically treating surfaces with materials such as polytretafluoroethylene‚ silicon‚ or wax. Another technique that can be used to increase the hydrophobic properties of a hydrophobic surface is to increase the surface area by increasing surface roughness. If a surface is initially
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Title: Penny Lab Experiment By -Objectives To determine how soap affects the surface tension of water. -Hypothesis In this experiment the hypothesis was that soap was going to affect the surface tension by weakening the bonds and allowing less water on the penny. -Materials * Penny * Beaker x2 (One containing soapy water the other containing pure tap) * Paper towels * Lab review sheet * Pencil * Pipette -Procedure First we picked who would drop the water onto
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Task 5 5th and 6th graders will be introduced to the concept of surface area of a cube. When doing so I would first begin by connecting previous learning with the new concept. These previous concepts are the prerequisite skills necessary to complete this task. Students will need to know how to compute for surface area. Some experience with using the equation (L x W) to compute for surface area is also helpful when advancing to surface area of a cube. Secure understanding of multiplication facts with
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Organ systems are specialised so that they can maximise the amount of materials exchanged over their membranes. The ways that effectiveness of an exchange surface can be increased are: Large surface area: a larger surface area means that more diffusion can occur at once. Thin membrane: this speeds up the exchange because the diffusion path is shorter so the molecules have less distance to travel. Efficient blood supply: In animals the blood system is very efficient for transporting a variety
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Viscosity of Liquids After studying the present lecture‚ you will be able to Define viscosity and viscosity coefficient Outline the method to measure viscosity using Ostwald viscometer Determine the average molecular weight of a polymer Determine the surface concentration of 1-butanol in aqueous solution Measure the distribution coefficient of a solute betweenn two solvents 39.1 Introduction Viscosity‚ one of the transport properties‚ arises because of intermolecular attractive and relatively long-range
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the cell? Hypothesis: The larger the cell is‚ the more difficult it will be for the chemicals to reach the centre of the cell‚ and diffuse throughout it. This is because there will be a higher surface-area to volume ratio in the larger cells‚ making the centre of the cells further away from the surface. Therefore‚ when dipped in sodium hydroxide‚ the larger cells will not be dyed pink all the way through like the smaller cells after the ten minutes. Materials: 1x1x1 cm agar cube 2x2x2 cm agar
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