the displacement y of the stone? | The stone‚ starting with zero velocity at the top of the building‚ is accelerated downward by gravity. | | Reasoning The upward direction is chosen as the positive direction. The initial velocity v0 of the stone is zero‚ because the stone is dropped from rest. The acceleration due to gravity is negative‚ since it points downward in the negative direction. Solution | 2). After 3.00 s of free-fall‚ what is the velocity v of the stone? Solution 1). A football game
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at a velocity of 80 km/h when he sees an old woman crossing the road 45 m away. He immediately steps hard on the brakes to get the maximum acceleration of 7.5 m/square second. how far will he go before stopping? Will he hit the old woman? 3. the time a male bungee jumper if freely falling is 1.5 seconds (a) What is the velocity of the jumper at the end of 1.5 s? (b) how high did he fall? 4. A juggler tosses three balls alternately vertically upward. each ball has an initial velocity of 5
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1 hour IB DIPLOMA PROGRAMME PROGRAMME DU DIPLÔME DU BI PROGRAMA DEL DIPLOMA DEL BI N07/4/PHYSI/HPM/ENG/TZ0/XX+ 88076501 Physics higher level PaPer 1 Thursday 8 November 2007 (afternoon) INSTRUCTIONS TO CANDIDATES • Do not open this examination paper until instructed to do so. • Answer all the questions. • For each question‚ choose the answer you consider to be the best and indicate your choice on the answer sheet provided. 8807-6501 21 pages © IBO 2007 –2– 1. Which
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30’+60’ = 90’=5400s=1.5h 40km+40km=80km vavg= 80000m/5400s=13.168724279835390946502057613169 m/s = 48 km/h 2. The coordinate of an object is given as a function of time by x = 7t – 3t2‚ where x is in meters and t is in seconds. Its average velocity over the interval from t = 0 to t = 2 s is: A) 5 m/s B) –5 m/s C) 11 m/s D) –11 m/s E) –14.5 m/s vt= 7-6t = 7-12=-5 m/s 3. The coordinate of a particle in meters is given by x(t) = 16t – 3.0t3‚ where the time t is in seconds. The
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1. Two ships P and Q are moving along straight lines with constant velocities. Initially P is at a point O and the position vector of Q relative to O is (6i + 12j) km‚ where i and j are unit vectors directed due east and due north respectively. The ship P is moving with velocity 10j km h–1 and Q is moving with velocity (−8i + 6j) km h−1. At time t hours the position vectors of P and Q relative to O are p km and q km respectively. (a) (b) (c) Find p and q in terms of t. (3) Calculate the distance
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along the circle‚ then:(a) its velocity changes but speed remains the same (b) its speed changes but velocity remains the same (c) both speed and velocity changes (d) both speed and velocity remains same 4. Which of the following statements is correct? (a) speed distance are scalar‚ velocity and displacement are vector (b) speed distance are vector‚ velocity and displacement are vector (c) speed and velocity are scalar‚ distance and velocity are vector (d) speed and velocity are vector‚ distance and displacement
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Exercises for Chapter 1 Kinematics 1. An impulsive retarding force of 3 seconds duration acts on a particle which is moving with a forward velocity of 60 m/s. The oscilloscope record of the deceleration is shown. Determine the approximate velocity of the particle at t = 9 s. [answer: -58 m/s] 2. A car can decelerate at 0.8 ‘g’ on a certain road. Find the total emergency stopping distance measured from the point where the driver first sights the danger for a speed of 100 km/hr. The time taken for
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INTRODUCTION A container terminal is a facility where cargo containers are transshipped between different transport vehicles‚ for onward transportation. The transshipment may be between ships and land vehicles‚ for example trains or trucks‚ in which case the terminal is described as a maritime container terminal. Alternatively the transshipment may be between land vehicles‚ typically between train and truck‚ in which case the terminal is described as an inland container terminal. Maritime container
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motion of objects without considering the effects that produce the motion. This experiment will show how to determine the linear motion with constant (uniform) velocity particularly the dynamic cart and linear motion with constant (uniform) acceleration‚ (e.g. free fall of motion). At the end of the experiment we found out that the velocity is a speed that involves direction of an object as well as the time. While for the acceleration‚ it is directly proportional to the distance or height but inversely
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s−1. b. Calculate its acceleration in m s−2. 3. A Prius hybrid car starts from rest and accelerates uniformly for 8.0s. It reaches a final speed of 16 m s−1. a. What is the acceleration of the Prius? b. What is the average velocity of the Prius? c. Calculate the distance travelled by the Prius. 4. A new model Subaru can start from rest and travel 400 m in 16 s. a. What is its average acceleration during this time? b. Calculate the final speed of the
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