IB Biology Potato Lab Table 1: Trial Number | Concentration of Sucrose Solution (M) ±0.2 ml | Initial Mass of Potato Core Slice(g) ±0.1 | Final Mass of Potato Core Slices (g) ±0.1 | 1 | 0.0 | 7.7 | 9.3 | 2 | | 6.0 | 8.1 | 3 | | 6.2 | 7.4 | 4 | | 10.2 | 13.2 | 5 | | 8.7 | 10.3 | 6 | | 4.9 | 6.0 | 7 | | 9.2 | 10.4 | 1 | 0.2 | 5.8 | 6.0 | 2 | | 11.6 | 12.1 | 3 | | 2.5 | 3.1 | 1 | 0.4 | 14.4 | 13.9 | 2 | | 2.6 | 2.8 | 3 | | 8 | 6.5 | 1 | 0.6 | 7.3 | 5.3 | 2
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amount of sucrose in the dialysis bag affected the amount of mass each bag loss or obtains. All the tubes contained different amount of sucrose concentrations. The higher molarity concentrations increased the movement of water to balance out the inside of the tube and the beaker. The greater amount of concentration gradient‚ in each tube‚ increased the rate of osmosis. This rate of osmosis is due to the net movement of water from an area of low concentration to an area of high concentration. Because
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Potato Catalysis Lab Pre-Lab Assignment Background Information: An enzyme is catalytic protein. It is the most important type of molecule found in living cells. Cells would not be able to function without enzymes. Enzymes speed up or slow down chemical reactions of the cells. It is usually easy to identify the names of enzymes because they end in -ase. The enzyme that acts upon the substrate hydrogen peroxide is usually called catalase. This enzyme is found in both plants and animals
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An investigation to find the water potential of potato and carrot tubers in a sucrose solution‚ of concentration 0.00 – 0.50Mol‚ over a 24 hour period Interpretation Written Communication C1 From our graph it can be seen that the concentration of sucrose solution is 0.18 M at 0% change in mass for the potato and 0.355 M at 0% change in mass for the carrot. I will use these values to find the solute potential by using the calibration graph. I will work out the water potential by using the
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Abstract The experiment was carried out to investigate at which point the potato has reached its isotonic environment. From the results‚ when the concentration increase to 0.3M‚ the mass of the potato slices decreased by -3.26%. We can conclude we see that as we increased the sucrose concentration it was a decrease in the percent change. Introduction All cells have membranes that are selectively permeable. In other words‚ they allow certain things in and certain substances are not allowed to
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diffusion from high concentration to low concentration. Some substances may be actively transported‚ which requires energy. The diffusion of water across a semi-permeable membrane is called osmosis. Osmosis is the net movement of molecules through a semi-permeable [1] membrane from an area of low solute concentration to an area with a high solute concentration. In this investigation‚ we are testing how concentration effects the rate of osmosis Hypothesis: The more hypertonic potato pieces are to a
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Cell Membrane—Potato Tuber Cells Introduction: Osmosis is a form of diffusion in which water diffuses through a selectively permeable membrane from a region of high concentration to a region of lower concentration. This form of diffusion takes place when the molecules in high concentration are too large to move through the membrane. Three factors that determine cell membrane permeability are shape‚ size‚ and polarity. For this experiment‚ it must be kept in mind that sucrose is not permeable
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bless you! Cassien TWAGIRIMANA ABSTRACT The Irish potato is one of major food tuber crops grown in Rwanda. It plays a key role in food consumption‚ nutritional security and reduction of hunger. Potato plant like other tuber crops requires sufficient supply of several essential elements for proper growth and function. It is a gross feeder and exploiting greater volume of soil nutrients including nitrogen‚ phosphorous‚ potassium and water. Potato production has become very important in Rwanda in
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Experiment: Turgor in Potato Tissue 1. We labelled three test tubes A‚ B‚ C‚ D and added initials of people in our group. 2. Used a syringe or graduated pipette to put 20 cm3water in tube A and 10 cm3 in tube B. 3. Put 20 cm3 of 17% solution in tube C and 10 cm3 in tube B; put 20 cm3 pure sucrose solutions in tube D. 4. Working on the dissecting board I cut the ends off large potato. I was careful with the knife and cut it onto the dissecting board away from myself. 5. Used a cork
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Aim: To investigate the effect of hydrogen peroxide concentration on enzyme catalase Indroduction: Enzymes are proteins. They function as biological catalysts. They lower the energy barrier of a reaction so that the reaction can take place at body temperature. Also‚ they can speed up Metabolic reactions without being changed or used up. During a reaction‚ an enzyme molecule combines temporarily with the substrate. When the reaction is complete‚ the enzyme molecules returns to its original dorm
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