Social Alchemy 2nd Quarter / SY 2012 – 2013 Eng’r. Josephine A. Ng CHM142L/B21 Concepcion‚ Jermin B. Group# 2 Experiment No. 1 ------------------------------------------------- MELTING POINT AND BOILING POINT OF ORGANIC COMPOUNDS ------------------------------------------------- ABSTRACT The melting point (MP) and the boiling point (BP) are probably the most widely used physical constant in the field of science. Determining the boiling point and the melting point of a compound helps you to characterize
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(2 marks) Q5. The Specific Heat of a substance is the energy (Joules) required to raise one gram of substance by one degree celsius‚ (units: J/goC) Heating 95.5 mL of a liquid from 18.5 oC to 47.9 oC takes 10515 J of energy. The density of the liquid at 18.5 oC is 1.210 g/mL. What is the Specific Heat of this liquid in this experiment? (3
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generalization 5. discrimination 6. extinction and spontaneous recovery 7. extinction Classical and Operant Conditioning 1. trembling (CC); running (OC) 2. drooling (CC); racing (OC) 3. foot dragging (OC); whimpering uncontrollably (CC) 4. hurrying (OC); heart beating faster (CC) 5. mouth watering (CC); sitting (OC) Negative Reinforcement or Punishment 1. negative reinforcement 2. punishment 3. negative reinforcement 4. negative reinforcement 5. punishment
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water is one of the components‚ and the liquid natural product being isolated (which is immiscible with water) is the other component. The product can be steam distilled from the natural source at a relatively low temperature (always less than 100 oC)‚ thus avoiding decomposition of the product.2 Steam distillation can be carried out in two ways: the direct method and the live steam method.3 In the direct method‚ steam is generated by boiling a mixture of the source of the compound of interest
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1 Chapter 1 Definition and Basic Concepts Thermodynamics is defined as the science of energy. Originally derived from Greek words : therme (heat) and dynamics (power) – descriptive of early attempts at conversion of heat into power. Modern interpretation includes all aspects of energy and energy transformations‚ power generation‚ refrigeration‚ and the relationships among properties of matter. There are two approaches in thermodynamics studies: (1) classical thermodynamics – a macroscopic
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Friedel-Crafts Alkylation of 1‚4-Dimethoxybenzene) was carried out by Ashley and me. Part I (nitration of methyl benzoate) was carried out by Jenny. Physical Quantity TableType of substanceMolecular FormulaMolecular Weight (g/mol)Density(g/cm3)M.P.(oC)B.P.(oC)Methyl benzoateC8H8O2136.161.094-15198-200Methyl 2-nitrobenzoateC8H7NO4181.141.289-13104Methyl 3-nitrobenzoateC8H7NO4181.14-78-80289Methyl 3‚5-dinitrobenzoateC8H6N2O6226.14544-106-109-Methyl 4-nitrobenzoateC8H7NO4181.15-94-96-1‚4-DimethoxybenzeneC8H10O2138
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_______________________________________________________________ _______________________________________________________________ Report Information from ProQuest May 27 2014 19:59 Created by My Research account: SMOK1024 (alonzo strom) _______________________________________________________________ 27 May 2014 ProQuest Table of contents 1. Screening for gynecological cancers........................................................................................................
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1. Objective The aim of this laboratory experiment is to analyse the rate of heat transfer losses through convection and radiation separately from a cylindrical glass rod suspended in a pressure vessel. The variation of the dimensionless quantities; Nusselt number‚ Prandtl number and Grashof Number‚ with Pressure are to be analysed graphically as well. The experimental graph of log10(Nu) vs log10(Gr.Pr) should be plotted and analysed against the graph of the empirical equations. 2. Introduction:
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because their concentration is lower outside. © UCLES 2005 5090/01/O/N/05 3 3 Which graph shows how an enzyme catalysed reaction in the alimentary canal varies with temperature? A B rate rate 0 10 20 30 40 50 60 70 temperature / oC C 0 10 20
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a. OC= average age of inventories + Average collection period 110+75= 185 days Cash conversion cycle= operating cycle –average payment period = 185-30= 155 days Resources needed= Annual OC Investment x CCC 365 =2650000 X 155 365 = 1125324.66 b. Operating cycle= Avg. age of inventories + Avg. collection period = 83+ 75 =158 days Cash conversion = operating cycle – avg. payment period = 158days- 39 days = 119 days Resources
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