Name _________________________________________ Date ______________ Period ______________ Chemistry Lab Mole: Measuring Mass as a Means of Counting Purpose: Determine the number of atoms that fit on one tea spoon. 1. Use one clean and dry 50 mL beaker. Place on a balance and press the zero button until the display shows 0.00. 2. Place one level teaspoon of sodium chloride (NaCl) into the beaker‚ determine the mass and record in the table (row 1). 3. Repeat steps 1-2 for CaCO3 4. Repeat steps 1-2
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Shawn Dubbs Lab 1 The Mole Concept of and the Chemical Formula of a Hydrate Abstract: The objective of this lab was to conduct an experiment to analyze the molar components in alum. This was conducted by heating the alum till the water had evaporated and then determining the number of moles for each component. Then using the these amounts to figure out the empirical formula for alum. Results: In order to determine how much of each separate component a total mass was taken before hand for
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of each element in BaCo3‚ assume we have 1 mole of BaCo3‚ we have M(Baco3)g=137.3+12.0+3x16.0=197.3g/mol so we have 197.3g Baco3 so 1mol of Ba=…… 8. %element=m(element)/m(compound)x100% 9. Empirical formula-----simplest whole number ratio Metallic elements and ionic substances--- EF=formula Covalent substances---EF may be the same or simple whole number ratio of the empirical formula. 10. mass(g) m/M moles(mol) divide by smallest simplest mole ratio-----EF 11. If it doesn’t give the exact
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lab we took Fe(NO3)3 and NaOH and mixed 7 different mole ratios in graduated cylinders to determine what the mole ratio is. We also did the same thing with solutions of CuCl2 and Na3PO4. We determine the mole ratios by graphing the volume of reactant #1 vs. volume of precipitate for each reaction. Data Part 1.) Cylinder 1 2 3 4 5 6 7 Fe(NO3)3‚ 0.1 M‚ ml 5 10 12 15 17 20 24 NaOH‚ 0.1 M‚ ml 55 50 48 45 43 40 36 Fe:OH mole ratio 1:11 1:5 1:4 1:3 2:5 1:2 2:3 Volume Precipitate
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Name Mole Lab Exercises I. Pre Lab Questions Answer the following questions. (Hint: Your textbook will be helpful.) 1. ‘s number is the number of carbon atoms that are present in 12 g of 12C. 2. How many molecules of a compound are in one mole of that compound? 3. Write out the formula for finding percent by mass. 4. Write out the formula for finding Molarity. 5. The Formula Weight of a compound is equal to mole of that compound.
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Mole Fraction Return to Solutions Menu The mole fraction is: moles of target substance divided by total moles involved The symbol for the mole fraction is the lower-case Greek letter chi‚ χ. You will often see it with a subscript: χsolute is an example. Example #1: 0.100 mole of NaCl is dissolved into 100.0 grams of pure H2O. What is the mole fraction of NaCl? Solution: 100.0 g / 18.0 g mol¯1 = 5.56 mol of H2O Add that to the 0.100 mol of NaCl = 5.56 + 0.100 = 5.66 mol total Mole fraction
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S. 5.2 – The Mole The mole: - - - - Ex. - Molar mass (g/mol): - - - Ex. |Element |Atomic mass shown on Periodic |Molar mass of element | | |table | | |N |14.0067 |14.0067 g
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underlying purpose in determining the relationship between moles evolved and consumed. This can be demonstrated by measuring the hydrogen gas evolved by performing a chemical experiment when hydrochloric acid reacts with the magnesium. The formulated reaction includes; Mg + 2HCl → H2 + Mg2+(aq) + 2Cl- (aq) The major findings contributing to the experiment is being able to determine and distinguish what moles have evolved thus being the hydrogen moles evolved allowing the magnesium to be consumed within
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Mole Ratio of a Chemical Reaction: Copper & Silver Nitrate Lab #4 OBJECTIVE In this experiment‚ you will determine the number of moles of reactants and products present in the reaction of copper and silver nitrate‚ and calculate their mole-to-mole ratio. The mole-to-mole ratio relating to the disappearance of copper and the formation of silver metal will be used to write the balanced equation for the reaction. The reaction of copper metal with silver nitrate solution is a single
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Determination of the mole ratio of a chemical reaction The method of continuous variations is a means of determining the stoichiometric mole ratio of the reactants in a chemical reaction. The stoichiometric ratio‚ as given by the coefficients in the balanced chemical equation‚ represents the ratio at which chemicals must be combined to produce all product with no excess reactant. Since there is no “wasted” reactant‚ the maximum amount of product is made for the given amount of both reactants
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