Ammonia and Hydrochloric Acid Lab Chemistry 1 Abstract The straw should be cut shorter to 8 cm in order to make the solid ring appear in the center of the straw. We achieved our goal‚ cutting the straw caused the gases to not have to go as far‚ and meet in the middle. Background The particles in a gas are very loose and tend to move around a lot very quickly. The particles in a solid are very compact and vibrate but don’t really move very much. The particles in a liquid however are more
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smaller than 0.85mm (Pass through 15 B.S. sieve) and bigger than 0.60mm (Retain at 25 B.S. sieve). A H M 531 Compressive and tensile strength of cement mortar By: Ahmed Essam Mansour The Civil Engineering Center 1 Visit www.AHM531.com for more lab reports and lecture notes! A H M 531 The Civil Engineering Center In the cement-sand mortar‚ the proportion between Cement and Sand is 1:3 and the W\C = 40%. The same mixture is used in the compressive test a nd in the tensile test. Apparatus
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A. What is the name of the pigment that captures light? Chlorophyll B. Why does the pigment appear green? It absorbs other colors of light such as red and blue‚ so in a way the green light is reflected out since the pigment does not absorb it. 2. List two variables besides the wavelength (color) of light which might affect the rate of food production in plants. Light intensity and carbon dioxide 3. Why is chlorophyll important for all biological life? It is necessary for photosynthesis which
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peroxidase. The three conditions tested were the effect of peroxidase concentration on the rate of the experiment‚ the effect of pH of the rate of peroxidase activity‚ and the effect of temperature on the rate of peroxidase activity. During the lab‚ the lab group tested 7 test tubes‚ including 1 blank‚ with different amounts of pH 5 buffer‚ H2O2‚ Peroxidase‚ and Guaiacol. After the certain amount of mL per substance was mixed‚ the absorbance readings for the effect of peroxidase concentration were
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Purpose: The purpose of this lab is to identify the presence of cations and anions in four unknown solutions by identifying whether they are copper‚ silver‚ iron‚ or chloride ions which is done by adding sodium hydroxide‚ solid copper‚ silver nitrate‚ and potassium thiocyanate to the solutions and analyzing the chemical reactions. Introduction: Chemical change‚ unlike physical change is the change in the composition of a substance rather than simply its shape‚ size‚ or state (Marie‚ 2015). Signs
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Through Dialysis Tubing (a Semi-Permeable Membrane) I. DESIGN A. PROBLEM/RESEARCH QUESTION 1. How does increasing molarity of sucrose affect osmosis through dialysis tubing? B. VARIABLES 1. The independent variable in this lab is the molarity of sucrose each dialysis bag is filled with. The time (30 minutes)‚ the temperature (23C) and the type of dialysis tubing used are all constants. 2. The dependent variable is the final mass of the dialysis bag. 3
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Question/Purpose: The Question or Purpose of our lab is to answer the question “How is the germination of a seed affected by sunlight?” Experimental Hypothesis: We believe these results will occur. 1. The seeds that are water deprived (1 mL of H2O a day) will not grow very well due to a lack of water which is important in photosynthesis and also lacks nutrients. The seeds may also die off due to a lack of water. 2. The seeds that are have a proper amount of water (10 mL of
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The completed calculations can be found on lab notebook page 14. Using this data‚ graph 2 was generated showing the relationship between the intensity ratio and the concentration of chlorine. Relating to the Stern-Volmer equation of F0/F=1+KSV[Q] and the linear line equation of y = 124x + 1.08‚
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Physiology‚ Berry HOMEOSTASIS LAB ACTIVITY Introduction: Homeostasis means maintaining a relatively constant state of the body’s internal environment. The term used to describe a pattern of response to restore the body to normal stable level is termed negative feedback. When a stimulus (environment change) is met by a response that reverses (negates) the trend of the stimulus‚ it is negative feedback. As a result the internal environment is returned to normal. Pulse rate is constantly checked
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Post-Lab Questions 1. Using the information provided in the Introduction and your observations from Part 1‚ hypothesize as to the type of electrolyte the following solutions would be. Justify the hypothesis from a chemical standpoint. a. Aqueous Sodium Hydroxide—NaOH (aq) is a very strong base‚ which will completely disassociate into Na+ and OH- ions‚ which would make it a very strong electrolyte. Chemical reaction of the disassociation of Sodium Hydroxide: NaOH (aq)Na+ (aq)+ OH-(aq)
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