1. The street of a city are arranged like the lines of a chessboard ‚ there are m street running north and south and n east and west . Find the no. ways in which a man can travel from N.W to the S.E corner‚ going by the shortest possible distance. 2. How many different arrangement can be made out of the letters in the ex-pression a^3b^2c^4 when written at full length? Ans. 1260. 3. How many 7-digit numbers exist which are divisible by 9 and whose last but one digit is 5? 4. You continue
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APPLICATION OF SINE LAW The shorter diagonal of a parallelogram is 5.2 m. Find the perimeter of the parallelogram if the angles between the sides and the diagonal are 40o and 30o10’. From the top of a 150 m lighthouse‚ the angles of depression of two boats on the shore are 20o and 50o‚ respectively. If they are due north of the observation point‚ find the distance between them. SOLUTION Solved for a 150/sin50 = a/sin90 a = (150 sin90)/sin50
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work a rough feeling by the lines being smooth and pointy. The texture in this piece of work is rough by the shapes created and the lines are smooth but also pointy that gives it a rough feeling and Jen Stark could of made this by making several triangles all the same size and kept sticking them together
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The use of questioning and paired work in Mathematics Traditionally‚ mathematics and language-based subjects have been seen as occurring on opposite sides of a great divide. However‚ in recent years teachers have realised the importance of talk across the curriculum including mathematics. This is supported by the DfEE (1999a‚ p11) who state that ‘high quality interactive teaching is oral‚ interactive and lively. It is a two way process in which pupils are expected to play an interactive role by
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CBSE IX | MATHEMATICS Sample Paper – 1 Solution CBSE Class IX Mathematics Term II Sample Paper - 1 Solution (SECTION – A) 1. Correct Answer: C Graph of equation x = k is parallel to the y-axis. 2. Correct Answer: B As this data will be available through some agency only and will not be collected by the student himself‚ it is known as secondary data. 3. Correct Answer: A The positive solutions of the equation ax + by + c = 0 always lie in the 1 st quadrant. 4. Correct Answer: C Perpendicular from
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TEN LITTLE FINGERS Ideas and Activities in Science Arvind Gupta Illustrations: Avinash Deshpande Ten Little Fingers is a collation of innovative toys and science activities which the author has tried and tested in more than one thousand schools over the past twenty years. With detailed illustrations‚ each activity is clearly depicted. Children do not need fancy laboratories and expensive equipment for doing science activities. There is much‚ which can be done using throwaway things found at
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point‚ line‚ and plane. 2. “The ray through point P from point Q” is written in symbolic form as PQ. 3. “The length of segment PQ” can be written as PQ. 4. The vertex of angle PDQ is point P. 5. The symbol for perpendicular is . 6. A scalene triangle is a triangle with no two sides the same length. 7. An acute angle is an angle whose measure is more than 90°. 8. If AB intersects CD at point P‚ then a pair of vertical angles. APD and APC are 9. A diagonal is a line segment in a polygon connecting
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section × length Area of trapezium = 1 (a + b)h 2 a cross section lengt h h b Volume of sphere = 4 3 U 3 Volume of cone = 1 2 Uh 3 Surface area of sphere = 4 U 2 r Curved surface area of cone = UO l r h In any triangle ABC C b A c a B The Quadratic Equation The solutions of ax2 + bx + c = 0 where D 0‚ are given by x= −b ± (b 2 − 4ac) 2a Sine Rule a b c = = sin A sin B sin C Cosine Rule a2 = b2 + c 2 – 2bc cos A Area of
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Mathematics: Their History and Solutions. Dover Publications New York‚ 1965. 197-200 3 Dörrie 127. 4 Eric W Weisstein‚ “Alhazen’s Billiard Problem”. Mathworld. Dated 1999. Viewed February 25 2006. Alexander Zouev 000051 - 060 - 4 - triangle whose legs pass through two given points inside the circle”. 5 My primary reason for choosing to investigate this focus question is that the I.B Higher Level
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MATHS-SA1-TEST1 Q1) Use the following information to answer the next question. The steps for finding the H.C.F. of 2940 and 12348 by Euclid’s division lemma are as follows. 12348 = a × 4 + b a = b × 5 + 0 What are the respective values of a and b? A. 2352 and 588 B. 2940 and 588 C. 2352 and 468 D. 2940 and 468 Answer The steps to find the H.C.F. of 12348 and 2940 are as follows. 12348 = 2940 × 4 + 588 2940 = 588 × 5 + 0 Comparing with the given steps‚ we obtain a =
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