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    Hemorrhagic Stroke

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    include: Intracerebral‚ and subarachnoid hemorrhage. Each year in the United States‚ approximately 795‚000 people experience new or recurrent stroke. Of these‚ approximately 610‚000 represent initial attacks‚ and 185‚000 represent recurrent strokes. Epidemiologic studies indicate that approximately 87% of strokes in the United States are ischemic‚ 10% are secondary to intracerebral hemorrhage‚ and another 3% may be secondary to subarachnoid hemorrhage. The incidence of stroke varies with age‚ sex‚ ethnicity

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    Chronic Sorrow

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    was considered as probability of chronic sorrow‚ and 83 to 108 was considered as chronic sorrow. In determining instrument reliability‚ Cronbach’s Alpha of 0.91 confirmed its high internal consistency. The simultaneous conduction with "Center of Epidemiologic Studies-Depression Scale (CES-DS)" and "General Wellbeing Scale (GWBS)" and the positive and negative significant correlation with the first and second instrument confirmed the construct validity of the instrument

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    Geometry Outline

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    1. Types of Reasoning * Inductive Reasoning – * general conclusion based on a limited collection of specific observations * educated guesses * Primary flaw – we cannot be sure the conclusion is always correct * Counterexamples -- show a conclusion reached through inductive reasoning is not true * Deductive Reasoning – * making a specific conclusion based on a collection of generally accepted assumptions. * There are no counterexamples

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    geometry semester 2 notes

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    to one of its sides. • p = ns • n = number of sides • s = length of each side IV. Area of a Regular Polygon  Area = ½ (p • a)  p = perimeter  a = apothem V. Square • Area of a square = a*a  a = length of side VI. Triangle • Area of a triangle= ½ b*h  b = base  h = vertical height VII. Parallelogram • Area of a parallelogram = b *h  b = base  h = vertical height VIII. Trapezoid • Area of a trapezoid = ½ (a + b) • h  a = 1st base  b = 2nd base  h = vertical

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    Operative Report

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    Williams‚ MD‚ Pulmonology Surgeon: Simon Williams‚ MD Preoperative Diagnosis: Recent onset hemoptysis‚ history of tuberculosis. Postoperative Diagnoses: No tuberculosis lesions seen. Surgical Procedures: Bronchoscopy. Specimen Removed: Blood clots. INDICATIONS: Mr. Barua requires bronchoscopy because of recent onset hemoptysis and a remote history of tuberculosis. PROCEDURE IN DETAIL: The patient was routinely premedicated with 25 mg of Demerol with 2 mg of Versed also used

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    Summary Of gothic horror What is horror? People find different things scary‚ so different people have different ideas about what horror actually is. A lot of people enjoy the feeling of being scared‚ reasons being that it gives them a thrill‚ lets them take a break from things in their life they may be bored of‚ they are trying to conquer something the really do have a fear of‚ or just because that’s who they are. Horror stories include things like suspense‚ surprise‚ a setting that gives that

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    Spherical Trigonometry

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    Spherical trigonometry Spherical trigonometry is that branch of spherical geometry which deals with the relationships between trigonometric functions of the sides and angles of the spherical polygons (especially spherical triangles) defined by a number of intersecting great circles on the sphere. Spherical trigonometry is of great importance for calculations in astronomy‚ geodesy and navigation. The origins of spherical trigonometry in Greek mathematics and the major developments in Islamic mathematics

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    Cervical Lymphadenopathy

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    The most common causes of CL are; infection‚ malignancy‚ bacterial pharyngitis‚ dental abscess‚ ear infections‚ infectious mononucleosis‚ head and neck cancer especially in older patients with history of smoking‚ thyroid cancer‚ lymphoma‚ and tuberculosis (Magsi‚ Jamro‚ Shaikh‚ & Sangi‚ 2013). The workup for CL consist of a comprehensive history and physical examination‚ laboratory tests‚ imaging studies‚ and sometimes tissue biopsy may be indicated. The history should focus upon demographic information

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    ExamView Ch 5 REVIEW

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    = JK A is the midpoint of IK . Name: ________________________ ____ ID: A 9. Find the center of the circle that you can circumscribe about the triangle. a. 1 (− ‚ –4) 2 b. (–3‚ −2) c. 1 (− ‚ −2) 2 ____ 10. Where can the bisectors of the angles of an obtuse triangle intersect? I. inside the triangle II. on the triangle III. outside the triangle a. I only b. III only c. I or III only ____ 11. In ∆ACE‚ G is the centroid and BE = 12. Find BG and GE. a. b. BG = 4‚ GE = 8 BG = 3‚ GE = 9 c.

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    terms by shweta101 Pythagorean Theorem In a right triangle‚ the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. (a^2 + b^2 = c^2 (Page­ 433) Pythagorean Triple A set of 3 positive integers A‚ B‚ and C that satisfy the equation A^2 + B^2 = C^2 [Ex. (3‚4‚5) (5‚12‚13) (8‚ 15‚17) and (7‚24‚25)] (Page­ 435) Converse of the Pythagorean Theorem If the square of the length of the longest side of a triangle (hypotenuse) is equal to the sum of the squares of the lengths of the

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