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    [ print page ] 04.05 Chemical Reactions: Combustion: Lab Worksheet and Rubric Before You Begin: You may either copy and paste this document into a word processing program of your choice or print this page. Procedure: 1. Iron (IIII) and copper (II) sulfate solution
Fill a small test tube halfway with copper (II) sulfate solution. Add a 2.0 gram iron rod to the solution and observe the reaction. 
 2. Lead (II) nitrate and potassium iodide solutions
Pour about 2.0 mL of lead (II) nitrate into

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    Introduction The purpose of this experiment is to determine the rate equation for the “Iodine Clock Reaction” experiment. The experiment will consider the equations 〖2I〗^-+S_2 O_8→2〖〖SO〗_4〗^(2-)+I_2 and I_2+2〖S_2 O_3〗^(2-)→2I^-+S_4 O_6 in order to determine the rate law of Rate=k[〖〖S_2 O_8〗^(2-)]〗^a 〖[I^-]〗^b by using the experimental data to calculate the values of exponents a and b as well as the rate constant k. Experimental Supplies Needed: 250 mL Erlenmeyer flask‚ 100 mL beaker‚ graduated

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    Introduction: A chemical reaction is formed of reactants and products. Reactants react with each other to give one or more product. Sometimes we can visualize observations that are characteristic of the reaction. Like for example a release of a gas (bubbles are formed) or a change of color or also the formation of a precipitate. Materiel needed: Test tubes Rack of test tubes Plastic droppers Beakers Procedure: We prepare 7 beakers of 7 different solutions (that we mark from 1→ 7)

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    Chem Exam - ‘98 1. Solve the following problem related to the solubility equilibria of some metal hydroxides in aqueous solution. (a) The solubility of Cu(OH)2(s) is 1.72 x10–6 g/100. mL of solution at 25° C. (i) Write the balanced chemical equation for the dissociation of Cu(OH)2(s) in aqueous solution. Cu(OH)2 Cu 2+ + 2 OH – (ii) Calculate the solubility (in mol/L) of Cu(OH)2 at 25 °C. (1.72 x10–6 g/0.100 L)(1 mol/97.5 g) = 1.76 x10–7 mol/L (iii) Calculate

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    Two-way reactions continue until equalibrium (the state at which there is balance between reactants and products) is reached. Discovering the equilibrium constant for a reaction is very helpful for understanding that reaction. Knowing the equilibrium constant of a reaction is important because it allows you to calculate how much product will ultimately be formed during a reaction. Moreover‚ it also tells you how a particular mixture of chemicals will react. This is because chemical reactions always

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    objective: In this experiment‚ I decided to find out how temperature would affect endothermic reactions compared to exothermic reactions. An endothermic reaction absorbs energy in the form of heat. This reaction feels cold because it is taking heat away from its surroundings. It also releases gases. An exothermic reaction is a reaction that releases energy as heat. Since the energy is released‚ the exothermic reactions feel hot. Methods/Materials I did three experiments. I mixed lemon juice and baking

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    difference between a mixture and a compound. A compound is a substance in which atoms of different elements are chemically held to one another. A mixture is a substance made by combining two or more different materials in such a way that no chemical reaction occurs. A mixture can usually be separated back into its original components‚ a compound cannot. Below are some examples of the differences between each. Compounds •Compounds are pure substances. •They are made up of two or more elements combined

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    The total protein content was estimated as proposed by Lowry et al. A bovine serum albumin stock solution (1mg/ml) was prepared in sodium hydroxide (1N). Five different concentrations (0.2‚ 0.4‚ 0.6‚ 0.8‚ 1 ml) of the prepared solution were taken in different test tubes. In another set of test tubes‚ 0.1 and 0.2 ml of the extract were taken. In each test tube‚ the volume was made up to 1 ml‚ followed by addition of the prepared alkaline solution (5 ml) at room temperature. The solutions were left

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    purpose of this lab was to find the theoretical and experimental percentage yields of the double displacement reaction between the solutions Lead (II) Nitrate (PbNO3) and Potassium Iodide (KI). It is important to obtain amounts of Lead (II) Nitrate and Potassium Iodide as close to 1.44g as possible. This reaction creates Lead (II) Iodide and Potassium Nitrate. The precipitate during this reaction is Lead (II) Iodide. The balanced equation is Pb(NO3)2 + 2KI= PbI2 + 2KNO3. In this lab the Lead (II) Iodide

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    A 70% B AS Level Chemistry 60% C 2008 – 2009 50% D 40% E Below U Questions on % Haloalkanes 2.8 32 1. Chloromethane can be prepared by a reaction between methane and chlorine in the presence of ultraviolet radiation. (i) Outline the mechanism for this reaction. ..................................................................................................................................... ..................................................

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