"Using the rate law the rate and the appropriate concentration s from one or more of your experiments calculate k" Essays and Research Papers

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    Rate of Diffusion

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    The Correlation between the Diffusion Rate of a Substance and its Molecular Weight ABSTRACT To test the effect of molecular weight on the rate of diffusion‚ various experiments were performed. One of which is the glass tube test wherein cotton balls of the same size were moistened in two different substances (NH4OH and HCl). These cotton balls were plugged at each side of a glass tube. After some time‚ formation of a white ring occurred. The white ring‚ in fact‚ is a product of the reaction between

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    movement of molecules from areas of higher concentration to those of lower concentration‚ until there is an even concentration. This movement is random because it is a result of kinetic energy. Diffusion is a slow process‚ but there are many factors that will affect it’s rate. The rate of diffusion will vary depending on the size of the particle. For example‚ a smaller particle will move faster than a large molecule at a given temperature . During reactions‚ when there is more energy‚ the reaction

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    The aim of this experiment was to investigate the effect that a glucose concentration has on the rate of fermentation. This was done by adding a variety of different glucose concentration into a test tube‚ siting in a water bath. The carbon dioxide would be collected in the test tube and therefore would measure the rate of fermentation. The results parsley supported the hypothesis that‚ “If the glucose concentration increases‚ the rate of fermentation increases‚ therefore the more carbon dioxide released”

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    Osmosis Rate

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    Effect of osmosis rate on different surface areas‚ depending on different types of water solution An investigation showing the effect of surface area on osmosis rate‚ including some different types of water concentration. Osmosis is a type of passive (not requiring energy) transport of water molecules across partially permeable membrane‚ from an area of high water concentration into area of low water concentration. But how does surface area affect rate of osmosis? Surface area plays important

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    expressions is the Henderson-Hasselbalch equation? (Points : 10)        pKa = pH + log        pH = pKa + log        pH = pKa + log        pKa = pH - log        pH = pKa + log 4. The Ksp of CaSO4 is 4.9  10-5 at 25 C. What is the concentration of Ca2+ in a saturated solution of CaSO4? (Points : 10)        2.4  10-9 M        2.5  10-5 M        4.9  10-5 M        7.0  10-3 M        3.7  10-2 M 5. What is the pH of the buffer that results when 12.5 g of NaH2PO4 and 22

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    Pulse Rate

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    this practical is to investigate how the pulse rate of humans changes when they exercise. Someone who is physically fit can supply their muscles with enough blood‚ carrying glucose and oxygen‚ for an activity at a lower heart and breathing rate. The fitter you are the lower your resting heart rate. You and your classmates will be the humans investigated. SAFETY: If you know you have any condition that affects you doing exercise‚ please make sure your teacher knows before you start the investigation

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    effect of substrate concentration Hydrogen Peroxide H O (in %) on the rate of reaction of the enzyme catalase (in 1/mean time). Prediction: As the substrate concentration (hydrogen peroxide) in % increases the rate of reaction in 1/mean rate increases until the solution becomes saturated with the substrate hydrogen peroxide. When this saturation point is reached‚ then adding extra substrate will make no difference. The rate steadily increases when more substrate is added because more of the active

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    Rate of Reaction

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    Aim: To determine the effect of altering concentration (mol dm-3) of hydrochloric acid (HCl) on the rate of reaction (mol dm-3 s-1) for the following chemical reaction: CaCO3(s) + HCl(aq) CaCl2(s) + H2O(l) + CO2(g) Research question: How does altering concentration (mol dm-3) of hydrochloric acid (HCl) affect the rate of reaction (g/s) for the following reaction: CaCO3(s) + HCl(aq) CaCl2(s) + H2O(l) + CO2(g) Background information: The reaction between calcium carbonate and hydrochloric acid

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    The reaction order‚ based on the rate law‚ was first order with respect to crystal violet and second order with respect to OH-. The rate law was as follows: Rate law = k [CV]1[OH-]1 where k equaled 2.61. In order to determine the reaction order with respect to crystal violet‚ the graph that described the relationship between ln[CV] and time (seconds) was Figure 2. Not only did Figure 2 generate a more linear relationship‚ but it had the highest R2 value of 0.992 than ([CV] versus time) and ([1/CV]

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    Chemical Kinetics and Rate

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    The Rate of a Reaction Chemical Kinetics is the area of Chemistry that is concerned with the speed‚ rate or mechanism at which a chemical reaction occurs. Reaction Rate is the change in the concentration of a reactant or product with time (i.e. M/s). It measures how fast a reactant is consumed and how fast a product is formed. 1.2 WRITING RATE EXPRESSIONS Consider the following hypothetical reaction. A + 2B ( 3C + D Rate = - rate of consumption of A = -[pic]rate of

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