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    Projectile Motion

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    Experiment 4 Projectile Motion Introduction We examined projectile motion by observing a ball rolling down then leaving the ramp‚ thus becoming a projectile with a horizontal initial velocity. We measured the horizontal initial velocity using the photogate and computer. We measured the horizontal and vertical distances that the projectile traveled from the end of the ramp to when it hit the floor my using a meter stick to measure Experimental Set-Up In our experiment‚ we used the following:

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    piston system shown‚ a piston P is connected to a crank AB (b 16 cm.) by a 2 kg slender rod B ( l 40 cm.). The mass of the crank AB can be considered to be very small. During a test of the system‚ crank AB is made to rotate with a constant angular velocity of 60 rad/s clockwise. There is no force applied to the face of the piston. When 60the distance between points D and A ‚ d‚ is 43.081 cm and the angle  of connecting rod BD from the horizontal is 30o. Consider this instant when 60‚ answer

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    Physics

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    position of a particle as it travels along the x-axis. At what value of t is the velocity of the particle equal to zero? (A) 1 s Answer: velocity = slope of x vs t line (B) 2 s slope = 0 at t = 3 s (C) 3 s (D) 4 s MCQ 2: A runner runs around a track consisting of two parallel lines 96 m long connected at the ends by two semicircles with a radius of 49 m. She completes one lap in 100 seconds. What is her average velocity? (A) 2.5 m/s ∆ (B) 5.0 m/s Answer: 0 m/s  ∆ ∆ (C) 10 m/s (D) 0 m/s MCQ 3: You

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    Thermal Sensitivity

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    average was taken and this was repeated for 5 animals at 15oC and 25oC. The calculated average velocity of the animal was also collated with class results and recorded in a table RESULTS Length-specific O2 consumption rate was shown to be slightly higher in the warmer temperature of 25oC compared to the O2 consumption rate of artemia at 15oC (Figure 1). Contrastingly‚ the opposite applies for velocity‚ with the artemia in the colder environment of 15oC showing faster speeds of movement in comparison

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    stopping distance

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    Stopping Distance and Reaction Time 20 m s -1 A B O positive direction 40 m The driver in the car B sees the man A 40 m away at time t = 0. The velocity of the car changes according to the graph below. V / m s-1 40 30 20 10 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 t/s V / m s-1 40 30 20 10 0 0.5 1.0 1.5 2.0 2.5 3.0 Will the car B collide with the man A ? 3.5 4.0 4.5 5.0 5.5 t/s

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    Introduction to Physics

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     slowing down‚speeding up‚ and turning provide a sufficient vocabulary for describing the motion of objects. In physics‚ we use these words and many more. We will be expanding upon this vocabulary list with words such as distance‚ displacement‚speed‚ velocity‚ and acceleration. As we will soon see‚ these words are associated with mathematical quantities that have strict definitions. The mathematical quantities that are used to describe the motion of objects can be divided into two categories. The quantity

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    Physics

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    physics 5/23/13 Constant motion Fill in the Blank (constant velocity) 1)Neither( ) nor ( ) of motion changes 2)y7ui8z Vocabulary Matching 3) A)how fast something moves; an expression of how much time it takes for a change in position to occur; rate of motion; rate of change of position( ) B)The speed of an object in a particular direction; ratio of change in position to time interval over which change takes place.( ) C)quantity having

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    Lab Report Catalase

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    production and reaction velocity increased with increasing catalase concentration‚ however‚ the 33% percent catalase concentration showed a drop of 0.175 mL O2/s compared to the 25% catalase concentration (figure 1.2). The velocity of 25% catalase was 0.275 mL/s‚ 33% was 0.1 mL/s‚ 50% was 0.435 mL/s‚ and 75% catalase was 0.575 mL/s (figure 1.1). The 50% catalase concentration produced the most O2 overall however the 75% catalase concentration had the fastest initial reaction velocity. Experiment III:

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    Physics Chapter 4

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    on a computer screen has a position of r = [4 cm + (2.5 cm/s2)t2]i + (5 cm/s)t j. a) Find the magnitude and direction of the dot’s average velocity between t = 0 and t = 2 s. b) Find the magnitude and direction of the instantaneous velocity at t = 0‚ t = 1 s‚ nd t = 2 s. c) Sketch the dot’s trajectory from t = 0 to t = 2 s‚ and show the velocities calculated in part (b). (a) Identify and Set Up:   From [pic] we can calculate x and y for any t. Then use Eq. (3.2)‚ in component

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    Circular Motion

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    path. In order to find the object’s velocity‚ one needs to find its displacement vector over the specific time interval. The change in position‚ or the object’s displacement‚ is represented by the change in r. Also‚ remember that a position vector is a displacement vector with its tail at the origin. It is already known that the average velocity of a moving object is ᐃd/ ᐃt‚ so for an object in circular motion‚ the equation is ᐃr/ ᐃt. IN other words the velocity vector has the same direction as the

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