apparatus as shown in the Diagram: 2. Cut wires to the following lengths: · 30cm · 60cm · 90cm · 120cm · 150cm 3. Attach the wire to the crocodile-clip leads and set voltage to 5 volts or 1.5 Volts 4. Take the reading from the ammeter and record in results table. 5. Repeat 4 times for each length of wire and find the
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AIM- OUR AIM WAS TO FIND OUT WHICH VARIABLES AFFECT RESISTANCE‚ AND WHICH ONE HAS THE GREATEST EFFECT. BACKGROUND INFORMATION: Resistance is the force that opposes the flow of electrons in a circuit. The equation for resistance is Ω=V/A. (Ohms equals Voltage divided by amps). Resistivity is a measure of how strongly a material opposes the flow of electrical current‚ There are four main factors that affect resistance: Length – this is because the electrons would bump into more atoms‚ the longer
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Thevenin Theorem It provides a mathematical technique for replacing for a given network‚ as viewed from two output terminals by a single voltage source with a series resistance. It makes the solution of complicated networks (particularly‚ electronic networks) quite quick and easy. The Thevenin’s theorem‚ as applied to d.c. circuits‚ may be stated as under: The current flowing through a load resistance RL connected across any two terminals A and B of a linear‚ active bilateral network is given
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used the graph in tetanus to calculate the speed of contraction and relaxation. Fourth‚ we rotated the femur clamp to adjust the muscle length and looked at the changed in response in volts‚ and found out the optimal length. In result‚ we found out the threshold voltage is about 0.2 volts and the plateau is at 2.2 volts‚ the summation started at 16Hz‚ and it reached tetanus at 64Hz‚ for the optimal length‚ we did not get enough time to finish it‚ and it should be somewhere higher then 35 mm. Introduction:
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Carrying Capacity of the cable (Iz): ...................................................... 3 Correct Cable Size: ................................................................................................ 3 Volt drop (Vd): ...................................................................................................... 4 Result ...............................................................................................................
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voltages to make the experiment fair then I will find the average. I will record the Voltage and the Current of the wire in every 10 meters. I will record my results in a format of a table like this. Length (cm) Current (I)(amperes) Voltage (V) (volts) Resistance ® (Ohms) 10m 20m 30m 40m 50m 60m 70m 80m 90m 100m For the Current and the Voltage there will be 3 results then I will find the Resistance and get the average from that. To find the
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by R3 and C3. The distance between each set‚ is defined by the C2 and R1. The Voltage input to the circuit‚ used 12 volt DC power from a car at all. The section capacitor C1 as a filter to smooth the flow. Transistor Q2 may be any number SM3180. The schematic shown here can be used as a circuit for Car brake light or headlight flasher for flashing two 10 watt 12 volt lamps in car or any vehicle. The heart of the circuit is a 555 timer IC‚ wired as an astable multivibrator in the circuit
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ammeters. Potential Difference (voltage) Electrical charge tends to move from points of high potential to points of low potential. The difference in potential between two points is called the potential difference or voltage and is measured in units of volts (V). Resistance For many devices‚ it is found that the potential difference appearing across a device is proportional to the current flowing through it. The connecting relationships is known as Ohm’s law and is written:V = IR where R is the resistance
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along X-axis (in microseconds) & the voltage is represented along Y-axis (in Volts). Figure: 5.4(b) Output voltage of the square inverter and driven signals for switches S1a‚ S3a‚ and S5a Output voltage of combined synchronous rectifiers and driven signals for switches S1a‚ S1b‚ and S5a are shown in Figure 5.4(c). Here time is represented along X-axis (in milliseconds) & the voltage is represented along Y-axis (in Volts). Figure: 5.4(c) Output voltage of combined synchronous rectifiers and
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Calculate the power dissipated in the 10kW. V. DATA Voltage and Current Measured Values By deactivating the 12V power source and replacing it by a wire I got: V5V = 2.0 Volts I5V = 0.20 mA By deactivating the 5V power source‚ replacing it by a wire‚ and in turn restoring the 12V source I got: V12V = -2.4 Volts I12V = -0.24 mA By leaving both power sources ON
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