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    Front/Back: . The side panels are rectangles. . . Left/Right: . The top is a rectangle. . . Top: . The bottim is a rectangle. . . Bottom: . The total surface area is:. The volume is the area of a trapezoidal face times the length. . . Subject: Cylinder volume Name: Andy I need to fill a 10 foot diameter by 35 foot long cylinder 85% full. Is there a way to calculate at what depth equals 85%? ie‚ if I put a stick in the tank would it be at 8.5 feet? | |

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    Trial Volume (CM3) Diameter (CM) Radius (CM) M&M Thickness (CM) 1 75 11.34 5.67 .743 2 83 12.68 6.34 .658 Table 2 – Direct Measurement Trial M&M Thickness (CM) 1 .642 2 .741 3 .683 Table 3 - Calculated Averages Method Calculated Average Thickness (cm) Indirect (from Table 1)

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    Implementing A CAD System TO Reduce Costs Introduction This report will analyze a proposal on how Woodbridge Foam could become more competitive through improvements in technology. This includes the saving of the companies money‚ shortening the design time for new products‚ decreasing quoting time and improving quality overall. By implementing a company wide CAD system‚ which would be networked together with each customer and all plants‚ these improvements could be achieved. Research will include

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    contribution to chem

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    of 11.9 J. Discussion: There were mistakes with equipment and the overall procedure. The measuring devices could account for some of the errors. A graduated cylinder was used to measure volume‚ but s buret or pipet provides better accuracy. Using a graduated cylinder leaves room for a crucial error in volume determination‚ which would then lead to errors in determination of mass‚ molar content of the solution etc. This means that an inaccurate amount of solution may have been poured into the cylinder

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    with 100 mL of water. Recorded it (170.5 g). To get the weight of the water we subtracted the weight of the water in the flask and the weight of the flask empty. (170.5 g - 77.6 g = 92.89 g) We knew we had to get the volume of the water‚ to do this we had to use the formula (mass = volume x density) and we got (92.89 g). We then repeated the process two more times to have a total of three trials. We could then find the precision and accuracy. To do this we used the accuracy formulas to find the absolute

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    Chapter 2 Review problems 1. Calculate the density of a piece of wood with a mass of 8.3 g and a volume of 5 cm3. 1.7 g/cm3 2. A spoonful of sugar with a mass of 8.8 grams is poured into a 10 mL graduated cylinder. The volume reading is 5.5 mL. What is the density of the sugar? 1.6 g/mL 3. A 10.0 gram pat of butter has a density of 0.862 g/mL. What is the volume of the butter? 11.6 mL 4. A sample of metal has a mass of 34.65 g. When placed in a graduated

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    LGT2106

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    retailer. Mass production have been using in its business‚ which means the products from M&S would have a high volume but low variety. // M&S requires a mass production of 600‚000 cards with a few designs‚ which the production size is much larger than the usual‚ that is about 8‚000 at a time on average. This meant M&S is on a high volume basis while the existing customers are on a low volume basis‚ usually done in batches. Also‚ M&S will not need frequently change over as it requires a mass production

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    for defect formation is 1.1 eV‚ while the density of AgCl is 5.50 12.47 The modulus of elasticity for titanium carbide (TiC) having 5 vol% porosity is 310 GPa. (a). Compute the modulus of elasticity for the nonporous material. (b). At what volume percent porosity will the modulus of elasticity be 240 GPa? Only the negative root is meaningful‚ and the value of the porosity is 17.1 vol%. 13.8 Compare the manner in which the aggregate particles become bonded together in clay-based mixtures

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    account for. External variables are eliminated more and more with the higher volume of paper clips as well. For example when a single paper clip was weighed‚ let say that there was finger oil or some other substance on the paper clip. This would have given an inaccurate measurement. However when given 30 paper clips the extremities for inaccurate measurements are hidden or dwindled from the end value due to the higher volume of paper

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    policy. ©2011 Edexcel Limited. GCSE Mathematics 2MB01 Formulae: Higher Tier You must not write on this formulae page. Anything you write on this formulae page will gain NO credit. Volume of prism = area of cross section × length Volume of sphere [pic]πr3 Volume of cone [pic]πr2h Surface area of sphere = 4πr2 Curved surface area of cone = πrl [pic] [pic] In any triangle ABC The Quadratic Equation The solutions of ax2+ bx + c = 0

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