[Type text] [Type text] [Type text] _An experiment on the effect of surface area to volume ratio on the rate of osmosis of Solanum tuberosum L._ BACKGROUND A cell needs to perform diffusion in order to survive. Substances‚ including water‚ ions‚ and molecules that are required for cellular activities‚ can enter and leave cells by a passive process such as diffusion. Diffusion is random movement of molecules in a net direction from a region of higher concentration to a region of lower concentration
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charge of a volume is commonly described by a quantity called the charge density or the charge distribution. When the electric field that arises from the charge distribution exhibits a volumetric symmetry‚ a handy relationship known as Gauss’s Law may be used to calculate the charge distribution of the volume. The charge volume of a ball or rod mill is expressed as the percentage of the volume within the liners filled with balls or rods. When the mill is stationary‚ the charge volume can be quickly
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normal breathing is about 500 mL‚ this volume of air is called the tidal volume.In addition‚Vital capacity is the largest volume of air an individual can move in and out the lungs.Human Lung capacity can be measured in many different ways‚ one way of measuring human lung capacity is by using a ballon.The purpose of this experiment is to determine the vital capacity of your lungs and to understand the relationship between tidal and reserve respiratory volumes. Materials balloon ruler Procedure Please
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GS104 Lab Report Experiment # 1 Measurement‚ Length‚ Mass‚ Volume‚ Density & Time David Case: January 17‚ 2015 Experiment #1 Measurement‚ Length‚ Mass‚ Volume‚ Density‚ & Time Objectives: To make basic distance‚ mass‚ density‚ and time measurements. To make calculations of volume and density‚ using proper units‚ and to practice using graphing software while graphing the relationship between the circumference of a circle and its diameter. Materials:
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cubes using the dimensions from above. 2. Obtain TEACHER’S SIGN-OFF BEFORE you proceed! 3. Submerge the potato cubes (cells) into the iodine solution for 20 minutes. 4. While you are waiting for 10 minutes‚ calculate the surface area‚ volume‚ and surface area to volume ratio for each of the 3 potato cubes (cells). AFTER 10 Minutes 5. Carefully remove the potato cubes (cells) from the iodine solution and place them on absorbent paper towels. 6. Cut each cell in half and observe the inside. 7
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capacity of our lungs is the volume of air our lungs can hold. Our lungs have a greater capacity than we use when we take a normal breath. Scientists use various terms to describe the different components of lung capacity. Tidal Volume is the amount of air breathed out in a single normal breath (inhalation and exhalation). The Inspiratory Reserve Volume is the amount of air you can inhale over and above a normal breath. The Expiratory Reserve Volume is the volume of air forced out of the lungs
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colder one. Research Question: How does the surface area to volume ratio affect heat loss in organisms? Hypothesis: I hypothesize that the larger the surface area to volume ratio‚ the more heat will be lost and vice versa. In this experiment‚ there will be a series of sizes of round bottom flasks‚ each having a different surface area to volume ratio. The smallest round bottom flask will have the biggest surface area to volume ratio‚ therefore the heat loss in that particular flask will be
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Lung Volume Activity The graph below is called a spirograph. It represents the amount of air that moves into and out of the lungs with each breath‚ as measured by a device called a spirometer. (The terms that are used to describe the features of a spirograph are explained below.) • Tidal volume is the volume of air that is inhaled and exhaled in a normal breathing movement when the body is at rest. • Inspiratory reserve volume is the additional volume of air that can be taken into the lungs
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Surface Area to Volume Ratio and the Relation to the Rate of Diffusion Aim and Background This is an experiment to examine how the Surface Area / Volume Ratio affects the rate of diffusion and how this relates to the size and shape of living organisms. The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen
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Name: ___________Naomi Scharf___________________________ Date: 3/17/11________________________ Student Exploration: Boyle’s Law and Charles’ Law Vocabulary: absolute zero‚ Boyle’s law‚ Charles’ law‚ Kelvin scale‚ pressure Prior Knowledge Question (Do this BEFORE using the Gizmo.) A small helium tank measures about two feet (60 cm) high. Yet it can fill over 50 balloons! How can such a small tank contain enough helium to fill so many balloons? _The tank is compressing the helium into a denser
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