Potato Osmosis Introduction: A shipwrecked sailor is stranded on a small desert island with no fresh water to drink. They know they could last without food for up to a month‚ but if they didn’t have water to drink they will be dead within a week. Hoping to postpone the inevitable‚ their thirst drives them to drink the salty seawater. They are dead in two days. Why do you think drinking seawater killed the sailor faster than not drinking any water at all? Today we explore the cause of the sailor’s
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Cells‚ Cell Division‚ and Cell Specialization Fundamentally Different Types of Cell Prokaryotic Cell- single celled: only DNA+ structure (“before nucleus”) E.g. zygote-complete DNA Eukaryotic Cell-multi-celled (“after nucleus”) Prokaryotes Eukaryotes DNA In “nucleoid” region Within membrane-bound nucleus Chromosomes Single‚ circular Multiple‚ linear Organelles None Membrane-bound organelles Size Usually smaller Usually larger- 50 times Organization Usually single-celled Often multicellular
Free Cell Eukaryote
Plant cells are eukaryotic cells that differ in several key aspects from the cells of other eukaryotic organisms. Their distinctive features include: A large central vacuole‚ a water-filled volume enclosed by a membrane known as the tonoplast maintains the cell’s turgor‚ controls movement of molecules between the cytosol and sap‚ stores useful material and digests waste proteins and organelles. A cell wall composed of cellulose and hemicellulose‚ pectin and in many cases lignin‚ is secreted by
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EXPERIMENT: TESTING OSMOSIS WITH A POTATO |LAB DATE: NOV. 23rd / 2012 | |CLASS: Y-11-C |PERIOD:C | OBJECTIVE The weight of the potato slices will increase‚ decrease‚ or remain the same? HYPOTHESIS There will be no net movement of water molecules into or out of the potato. MATERIALS LIST |Large potato
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experiment‚ you will study osmosis. Your task is to design an experiment that will determine what concentration of solute is isotonic with the specimen cells. (Design) Procedure: You will be provided with the following materials: Potato‚ potato corer‚ scalpel‚ forceps‚ electronic balance 10 % salt solution‚ distilled water‚ 50 mL beakers‚ graduated cylinder‚ paper towel You must design a procedure that will enable you to determine the concentration of salt that is
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Discover Your Products’ Hidden Potential by Ian C. MacMillan and Rita Gunther McGrath A simple matrix helps you identify the attributes that will make your goods and services most competitive. Why did a minor math error that would occur only once every 27‚000 years so enrage customers that it briefly threatened to derail Intel’s Pentium chip? And how could a feature as trivial as an inexpensive cup holder swing millions of customers to purchase a $17‚000 automobile—particularly when only
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Making a Potato Powered Light Bulb Materials: A large potato Two pennies Two zinc-plated nails or screws Three pieces of copper wire A very small light bulb or LED light 1) Get a potato and cut it in half. Then make a small slit in each half just big enough to put a penny into. 2) Cut two pieces of copper wire and wrap one around one of the pennies a few times‚ and wrap the other one around the other penny a few times as well. 3) Take a third piece of copper
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Potato Enzyme Lab Enzymes are protein catalysts that speed up chemical reaction in living organisms. The purpose of this lab was to; observe the breakdown of hydrogen peroxide toxin by potato’s enzyme catalase‚ determine factors that influence how quickly the reaction takes place‚ and determine factors that influence how well enzymes function. The first test‚ we were supposed to see what would happen when we add sand in hydrogen peroxide. We filled a test tube with 5mL hydrogen peroxide and we added
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Redox potential – CV Acetonitrile Adjusted sensitivity Each ;line represents diff scan rates all been overlayed on one digarm Scan rates ranged from 0 .1 s-1 to 1 Peak due to iodide oxidation is read from +peak to – peak bottom line. Iodide to triiodide Glycol Didn’t work Using equation ip = 2.69 ×105 n3/2 A D1/2 C ν1/2 compare to linear equation y = mx+c y = peak current x = V1/2 c = zero Therefore m is = everything else C = concentration 0.05 M ethylene glycol (acetonitrile
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THE WORK DONE BY A CONSERVATIVE FORCE ALWAYS HAS FOUR PROPERTIES: 1. It can be expressed as the difference between the initial and final values of a potential-energy function. 3. It is independent of the path of the body and depends only on the starting and ending points. 2. It is reversible. 4. When the starting and ending points are the same‚ the total work is zero. The total mechanical energy ME = K + U is constant. Object moving in a uniform gravitational field gravitational a
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