Partial degradation of glucose Uses no O2 Yields some ATP Cellular respiration Complete degradation to CO2 and H2O Requires O2 = aerobic Yields much more ATP 2. Describe the summary equation for cellular respiration. Also note the specific chemical equation for the degradation of glucose. Organic compounds + O2 è CO2 + H2O + energy C6H12O6 + 6O2 è 6CO2 + 6H2O + energy (ΔG = -686 kcal/mol) Redox reactions: Oxidation and Reduction
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Exercises and Problems - Week 6 XACC/291 12/21/2014 Exercises and Problems - Week 6 Before After After Action Dividend Stock Split Stock holders’ equity Paid in capital Common stock‚ $10 par $ 600‚000 $630‚000 $600‚000 Paid in capital in excess par value $0. $12‚000 0 Total paid in capital $600‚000 $642‚000 $600‚000 Return earnings $900‚000 $858‚000 $900‚000 Total stock holders’ equity
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Solving Exponential and Logarithmic Equations Exponential Equations (variable in exponent position) 1. Isolate the exponential portion ( base exp onent ): Move all non-exponential factors or terms to the other side of the equation. 2. Take ln or log of each side of the equation. • Make sure to use ln if the base is “e”. Then remember that ln e = 1 . • Make sure to use log if the base is 10. • If the base is neither “e” nor “10”‚ use either ln or log‚ your choice.. 3. Bring the power (exponent)
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mathematics at a deeper level. Review of homogeneous equations The homogeneous constant coefficient linear equation an y (n) +· · ·+a1 y +a0 y = 0 has the characteristic polynomial an rn +· · ·+a1 r+a0 = 0. From the roots r1 ‚ . . . ‚ rn of the polynomial we can construct the solutions y1 ‚ . . . ‚ yn ‚ such as y1 = er1 x . We can also rewrite the equation in a weird-looking but useful way‚ using the symbol d D = dx . Examples: equation: y − 5y + 6y = 0. polynomial: r2 − 5r + 6 = 0. (factored):
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References: Kimmel‚ P.‚ Weygandt‚ J.‚ & Kieso‚ D. (2003). Essentials of accounting: Tools for business decision making (2nd ed.). Hoboken‚ NJ: Wiley. (pages 343- 346)
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of -1. Straight Lines: Equation of a straight line is y = mx + c‚ where m = gradient‚ c = y-intercept. The equation of a line‚ if we know one point and the gradient is found using: (y - y1) = m(x - x1) (If given two points‚ find the gradient first‚ and then use the formula.) Two lines meet at the solution to their simultaneous equations. Note: When a line meets a curve there will be 0‚ 1‚ or two solutions. 1. Use substitution to solve the simultaneous equations 2. Rearrange them to form a quadratic equation
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Why It Couldn’t Be The short story Cold Equations by Tom Godwin takes place on a ship called EDS. The space cruiser is piloted by a man named Barton. He has an order of killing the stowaway who snuck onto the ship because the weight on the EDS is too much for the ship to handle. In the process of hunting down the stowaway‚ he realizes it was a young innocent girl named Marilyn. Once Barton understands what kind of person Marilyn is‚ he doesn’t kill her immediately because he knows her reasons were
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Checkpoints – Check ‘Em Off the Checklist To the San Luis Obispo Police Department: The Pack family was one that was very well regarded throughout the Danville community. Parents Bob and Carmen had two little children‚ ten year old Troy and his seven year old sister Alana‚ both of which attended Sycamore Valley Elementary School with my brother and me. Troy was a pretty big kid‚ and even though he was a grade below us‚ I remember my friends and I would always try to pick him on our football
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formulas for: a. 75.69% C; 8.80% H; 15.51% O; MW = 206 b. 59.0% C; 7.1% H; 26.2% O; 7.7% N; MW = 180 1. Write (a) complete-formula equation‚ (b) ionic equation‚ (c) net ionic equation for this neutralization reaction: KHSO4 (aq) + NaOH (aq) → ? 2. In each of the following cases‚ predict whether a reaction will occur‚ and‚ if so‚ write the net ionic equation for the reaction: a. ZnSO4 (aq) + BaS (aq) → ? b. NaHCO3 (aq) + Ca(OH)2 (aq) → ? 3. Assign an oxidation number to each atom in: a.
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Basic equations of fluid statics | | | | | | | | | | | | | | | | An equation representing pressure field P = P (x‚ y‚ z) within fluid at rest is derived in this section. Since the fluid is at rest‚ we can define the pressure field in terms of space dimensions (x‚ y and z) only. Consider a fluid element of rectangular parellopiped shape( Fig : L - 7.1) within a large fluid region which is at rest. The forces acting on the element are body and surface forces. | | Body force
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