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    chemistry in daily life

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    II PUC – CHEMISTRY (34) MODEL QUESTION PAPER - 1 Time: 3hours 15 minutes Maximum marks: 70 Instructions: 1. The question paper has four parts: A‚ B‚ C and D. All parts are compulsory. 2. Write balanced chemical equations and draw labeled diagrams wherever required. 3. Use log tables and the simple calculator if necessary. (Use of scientific calculators is not allowed) PART-A I. Answer ALL of the following. (Each question carries 1 mark) 10x1=10 (Answer each question in one word or

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    Guess Paper – 2009 Class – X Subject – Chemistry (P- Block Elements) Kalra sir 09460472649 kalra1977@rediffmail.com Group 15 elements: |Symbol |Atomic |Electronic configuration | | |number | | | |7 |[He]2s22p3 | |N | | | |P |15 |[Ne] 3s23p3 | |As |33 |[Ar]3d104s24p3

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    Notes of Halo Alkanes

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    163 CHAPTER 13 HYDROCARBON  Hydrocarbons are composed of Carbon and hydrogen.  The important fuels like Petrol‚ kerosene‚ coal gas‚ CNG‚ LPG etc. are all hydrocarbons or their mixture. Sources: Petroleum and natural gas are the major sources of aliphatic hydrocarbon while coal is an important source of aromatic hydrocarbons. The oil trapped inside the rocks is known as petroleum. PETRA – ROCK‚ OLEUM – OIL. The oil in the petroleum field is covered with a gaseous mixture known as natural

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    Introduction The purpose of this experiment was to find the identity of the unknown compound #12. This was done both qualitatively and quantitatively. The qualitative observations were used to determine the functional group that was in the unknown‚ the quantitative results were used to determine the molar mass through Duma’s method. The types of compounds that were used in testing were all functional groups‚ Aldehyde‚ Ketone‚ Alcohol and‚ Ester. Functional groups are a portion of a molecule that

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    Class 10th Science Syllabus COURSE STRUCTURE CLASS X First Term: Marks: 90 Units Marks I. Chemical Substances: 33 II. World of living : 21 III. Effects of Current : 29 IV Natural Resources : 07 Total :90 Theme: Materials (30 Periods) Unit: Chemical Substances - Nature and Behavior Chemical reactions: Chemical Equation‚ Balanced chemical equation‚ implications of a balanced chemical equation‚ types of chemical reactions: Combinations‚ decomposition

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    Pressure and Gas

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    1) A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 L to 2.00 L at constant temperature. After the compression‚ the gas pressure was __________ atm. A) 4.00 B) 2.00 C) 1.00 D) 8.00 E) 16.0 2) A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is __________ atm. A) 1.5 B) 7.5 C) 0.67 D) 3.3 E) 15 3) A balloon originally had a volume of 4.39 L at 44 °C and a pressure of 729 torr. The

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    Chem 16 2nd LE Notes

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    Chem 16 Notes UPD Should only be a supplement to discussions Table of Contents* [A] Lecture [1] Thermodynamics [2]Energy [3]Enthalpy [4]Hess’s Law [5]Determining Enthalpy [6]Heat Capacity [7]Calorimetry [8] Entropy [9] Gibb’s Free Energy [10] Waves [11] Quantum Theory [12] Quantum Numbers [13] Electron Configuration [14] Periodic Table [15] Periodic Trends KSev [16] Chemical Bonding [17] Formal Charge [18] Resonance Structure [19] Bonds [20] VSEPR [22] Valence Bond Theory [22] Molecular Orbital

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    Astm E3-95

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    M EDesignation: E 3 – 95 An American National Standard Standard Practice for Preparation of Metallographic Specimens1 This standard is issued under the fixed designation E 3; the number immediately following the designation indicates the year of original adoption or‚ in the case of revision‚ the year of last revision. A number in parentheses indicates the year of last reapproval. A superscript epsilon (e) indicates an editorial change since the last revision or reapproval. This standard

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    Inter Molecular Spacing

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    Mark Scheme (Results) Summer 2012 International GCSE Chemistry (4CH0) Paper 1C Science Double Award (4SC0) Paper 1C Edexcel Level 1/Level 2 Certificate Chemistry (KCH0) Paper 1C Science (Double Award) (KSC0) Paper 1C Edexcel and BTEC Qualifications Edexcel and BTEC qualifications come from Pearson‚ the world’s leading learning company. We provide a wide range of qualifications including academic‚ vocational‚ occupational and specific programmes for employers. For further information‚

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    Volumetric Titration

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    2(22.99)+1(12.01)+3(16)g/mole = 0.2329g 105.99g/mole =2.197×10-3 moles From the equation ‚ 1 Mole Na2C03 react 2 mole HCl So‚ 2.197×10-3 moles Na2C03 = 2.197×10-3x 2 1 = 4.394x10-3 mole HCl Thus‚molarity HCl = n/v = 4.394x10-3 mole 42.87x10-3L = 0.1025 M. The suitable indicator is phenolphthalein. Primary standard

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