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Chapter 14 Solutions

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Chapter 14 Solutions
Solutions for Review Problems of Chapter 14
1. a. Given the following diagram for a product, determine the quantity of each component required to assemble one unit of the finished product.

b.

Draw a tree diagram for the stapler:

a.

F: 2 J: 2 x 2 = 4 D: 2 x 4 = 8

G: 1 L: 1 x 2 = 2 J: 1 x 2 = 2

H: 1 A: 1 x 4 = 4 D: 1 x 2 = 2

Totals: F = 2; G = 1; H = 1; J = 6; D = 10; L = 2; A = 4 b.

Stapler

Top Assembly

Base Assembly

Cover

Spring

Slide Assembly

Base

Strike Pad

Rubber Pad 2

Slide

Spring

2.

The following table lists the components needed to assemble an end item, lead times, and quantities on hand.

a. b.

If 20 units of the end item are to be assembled, how many additional units of E are needed? (Hint: You don’t need to develop an MRP plan to determine this.) An order for the end item is scheduled to be shipped at the start of week 11. What is the latest week that the order can be started and still be ready to ship on time? (Hint: You don’t need to develop an MRP plan for this part either.)

a. B: 20 x 2 = 40 – 10 = 30 E: 30 x 2 = 60 – 12 = 48

C: 20 x 1 = 20 – 10 = 10 E: 10 x 2 = 20
End Item

D: 20 x 3 = 60 – 25 = 35 E: 35 x 2 = 70

Total: 48 + 20 + 70 = 138 b.
B(2)

C

D(3)

E(2)

F(3)

G(2)

E(2)

H(4)

E(2)

Total LT 4 5 5 5 6 The longest sequence is 6 weeks. Week 11 – 6 weeks = Week 5.

5

3.

End item P is composed of three subassemblies: K, L, and W. K is assembled using 3 Gs and 4 Hs; L is made of 2 Ms and 2 Ns; and W is made of 3 Zs. On-hand inventories are 20 Ls, 40 Gs, and 200 Hs. Scheduled receipts are 10 Ks at the start of week 3, 30 Ks at the start of week 6, and 200 Ws at the start of week 3. One hundred Ps will be shipped at the start of week 6, and another 100 at the start of week 7. Lead times are two weeks for subassemblies and one week for components G, H, and M. Final assembly of P requires one week. Include an extra 10 percent scrap allowance in each planned order of G. The minimum order size for H is 200 units. Develop each

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