Enzyme Catalysis Lab Report
Candace S. Randolph
MISEP Cohort 2
Chemistry 512
Enzyme Catalysis Lab Report
Pre-lab Questions:
1. Write a balanced chemical equation with state symbols for the reaction catalyzed by peroxidase.
2H2O2 2H2O + O2
(4H1 4O) (4H + 2O + 2O)
2. What is the substrate(s) of this reaction? What is the catalyst?
Substrate = H2O2 hydrogen peroxide
Catalyst = peroxide
3. At what approximate temperature do enzymes normally operate in the body of a warm-blooded animal? Would your answer change if the enzyme came from a plant or yeast?
Enzymes normally operate in the body of a warm-blooded animal at the range of approximately 75°F - 100°F. If the enzyme came from a plant or yeast it would probably operate at a different temperature.
4. What allows peroxidase to be specific for its substrate? (In other words, why doesn’t peroxidase catalyze other types of reactions?)
Peroxidase is specific to its substrate because of its shape.
1
Experimental Lab:
Abstract:
An enzyme is a protein that serves as a biological catalyst (Denniston,
2007). A catalyst is any substance that increases the rate of a chemical reaction
(by lowering the activation energy of the reaction) (Denniston, 2007). In this experiment we are using Hydrogen peroxide (the substrate for this experiment) is.
Peroxidase is a soluble enzyme normally found in the cytoplasm of cells. Our experimental design was to find out if decreasing the amount of substrate will affect the reaction rate of the enzyme. For this experiment we used yeast as our peroxidase. The amount of enzyme was kept constant for this experiment.
Because the catalyst remained constant the group’s original hypothesis was, as we decrease the amount of substrate reaction will speed up. (The slope of the line will get steeper.) We decreased the amount of substrate for each reaction assuming that the result would increase the reaction rate of the reaction.
Materials:
Water
Yeast (enzyme)
Test tubes
Stoppers
Logger Pro and Laptop computer
Substrate
MISEP Cohort 2
Chemistry 512
Enzyme Catalysis Lab Report
Pre-lab Questions:
1. Write a balanced chemical equation with state symbols for the reaction catalyzed by peroxidase.
2H2O2 2H2O + O2
(4H1 4O) (4H + 2O + 2O)
2. What is the substrate(s) of this reaction? What is the catalyst?
Substrate = H2O2 hydrogen peroxide
Catalyst = peroxide
3. At what approximate temperature do enzymes normally operate in the body of a warm-blooded animal? Would your answer change if the enzyme came from a plant or yeast?
Enzymes normally operate in the body of a warm-blooded animal at the range of approximately 75°F - 100°F. If the enzyme came from a plant or yeast it would probably operate at a different temperature.
4. What allows peroxidase to be specific for its substrate? (In other words, why doesn’t peroxidase catalyze other types of reactions?)
Peroxidase is specific to its substrate because of its shape.
1
Experimental Lab:
Abstract:
An enzyme is a protein that serves as a biological catalyst (Denniston,
2007). A catalyst is any substance that increases the rate of a chemical reaction
(by lowering the activation energy of the reaction) (Denniston, 2007). In this experiment we are using Hydrogen peroxide (the substrate for this experiment) is.
Peroxidase is a soluble enzyme normally found in the cytoplasm of cells. Our experimental design was to find out if decreasing the amount of substrate will affect the reaction rate of the enzyme. For this experiment we used yeast as our peroxidase. The amount of enzyme was kept constant for this experiment.
Because the catalyst remained constant the group’s original hypothesis was, as we decrease the amount of substrate reaction will speed up. (The slope of the line will get steeper.) We decreased the amount of substrate for each reaction assuming that the result would increase the reaction rate of the reaction.
Materials:
Water
Yeast (enzyme)
Test tubes
Stoppers
Logger Pro and Laptop computer
Substrate