exercise 18

1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (-53.68,64.64), Where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places.

X =5.48, SD = 22.93
5.48 – 1.96(22.93) = AND 5.48 + 1.96(22.93) =
5.48 – 44.9428 = AND 5.48 + 44.9428 = -39.4628 AND 50.422 (-39.46, 50.42)

2. Which of the following values from Table 1 tells us about variability of the scores in a distribution?
a. 60.22
b. 11.94
c. 22.57
d. 53.66
C. 22.57
3. Assuming that the distribution for General Health Perceptions is normal, 95% of the females’ scores around the mean were between what values? Round your answer to two decimal places.

X = 39.71, SD = 25.46
39.71 – 1.96(25.46) = AND 39.71 + 1.96(25.46) =
39.71 – 49.9016 AND 39.71 + 49.9016
-10.4916 AND 89.6116
(-10.49, 89.61)

4. Assuming that the distribution of scores for pain is normal, 95% of the men’s scores around the mean were between what two values? Round your answer to two decimal places.

X = 52.53, SD = 30.90
52.53 – 1.96(30.90) AND 52.53 + 1.96(30.90)
52.53 – 60.564 AND 52.53 + 60.564
-8.034 AND 113.094
(8.03, 113.09)

5. Were the body image scores significantly different for women versus men? Provide a rationale for your answer.

Body image scores (0–100 scale) were significantly higher for women (73.1 +/- 16.93) than men (60.2 +/- 16.98), as stated in the relevant study results.

6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the men’s mental health scores around the mean in this distribution? Round your answer to two decimal places.

99% of the men’s mental health scores are around the mean of 57.09%.

7. Assuming that the distribution of scores for Physical Functioning in woman is normal, where are 99% of the women’s scores around the mean in this distribution? Round your answer to two decimal places.

99% of the women’s