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Lab 5
Title: Thévenin and Norton Equivalent Circuits.
Objective: The student will be able to find the Thévenin and Norton equivalents of a series-parallel circuit both analytically and by taking measurements.
Equipment: Power Supply
Digital Multimeter
BreadBoard
Preparation: Write the title and a short description of this lab in your lab book.
Make sure the page is numbered and make an entry in the table of contents for this lab.
Measure the actual resistance of your resistors (unless you have already done so) and use them in place of the standard resistor values throughout the remainder of the lab.
Thevenin's Theorem states that we can replace entire network by an equivalent circuit that contains only an independent voltage source in series with an impedance (resistor) such that the current-voltage relationship at the load is unchanged.
Norton's Thereom is identical to Thevenin's Theorem except that the equivalent circuit is an independent current source in parallel with an impedance (resistor). Therefore, the Norton equivalent circuit is a source transformation of the Thevenin equivalent circuit
Note: When there are only dependent sources, the equivalent network is merely RTh, that is, no current or voltage sources.
Note: When there are only dependent sources, the equivalent network is merely RTh, that is, no current or voltage sources.
Vth=Voc=VR2.2k
VR=IR
I=10/3.2K=3.125 mA
Vth=6.875 volt
IN=Isc
Vth=Rth*Isc that is Isc=Vth/Rth=6.875/1007.5=6.8mA
Rth=1007.5 ohm. if consider the RL=1K& RL=10K WILL HAVE RL | I (mA) | V (volts) | P (watts)p=i*v | 1k | 3.64 | 3.6 | 13.104 mw | 10k | 0.63 | 6.32 | 3.9816 mw |
2:consider the figure4.
therefore:_
Vth=9.14 volts, Rth=1.4k, IN=Isc=Vth/Rth=9.14/1.4k=6.528mA if RL=1K & RL=10K. RL | V(volts) | I(mA) | P(i*v)mw | 1k | 6.17 | 5.22 | 32.207 | 10k | 8.4 | 0.85 | 7.14 |
3:consider he following figure(5).
Conclusions: In the conclusion
Title: Thévenin and Norton Equivalent Circuits.
Objective: The student will be able to find the Thévenin and Norton equivalents of a series-parallel circuit both analytically and by taking measurements.
Equipment: Power Supply
Digital Multimeter
BreadBoard
Preparation: Write the title and a short description of this lab in your lab book.
Make sure the page is numbered and make an entry in the table of contents for this lab.
Measure the actual resistance of your resistors (unless you have already done so) and use them in place of the standard resistor values throughout the remainder of the lab.
Thevenin's Theorem states that we can replace entire network by an equivalent circuit that contains only an independent voltage source in series with an impedance (resistor) such that the current-voltage relationship at the load is unchanged.
Norton's Thereom is identical to Thevenin's Theorem except that the equivalent circuit is an independent current source in parallel with an impedance (resistor). Therefore, the Norton equivalent circuit is a source transformation of the Thevenin equivalent circuit
Note: When there are only dependent sources, the equivalent network is merely RTh, that is, no current or voltage sources.
Note: When there are only dependent sources, the equivalent network is merely RTh, that is, no current or voltage sources.
Vth=Voc=VR2.2k
VR=IR
I=10/3.2K=3.125 mA
Vth=6.875 volt
IN=Isc
Vth=Rth*Isc that is Isc=Vth/Rth=6.875/1007.5=6.8mA
Rth=1007.5 ohm. if consider the RL=1K& RL=10K WILL HAVE RL | I (mA) | V (volts) | P (watts)p=i*v | 1k | 3.64 | 3.6 | 13.104 mw | 10k | 0.63 | 6.32 | 3.9816 mw |
2:consider the figure4.
therefore:_
Vth=9.14 volts, Rth=1.4k, IN=Isc=Vth/Rth=9.14/1.4k=6.528mA if RL=1K & RL=10K. RL | V(volts) | I(mA) | P(i*v)mw | 1k | 6.17 | 5.22 | 32.207 | 10k | 8.4 | 0.85 | 7.14 |
3:consider he following figure(5).
Conclusions: In the conclusion