BY: Geordan Nichols
IMP Period 4-5
September 19, 2013 – October 2, 2013
Part one: Problem Statement A farmer is taking her eggs to the market in her cart when she hits a pot hole. When she goes to check on her eggs and they all broke! So she goes to claim her insurance. The agent asks how many eggs were in her cart and she does not remember! The only thing she could remember is that if she put the eggs in groups of seven there would be none left over. So I bet you think the answer is forty-nine right? Well I’ve got some bad news. The answer isn’t forty-nine. Well why you ask? You expected forty-nine because it was the simple answer. I know that forty-nine is wrong because if you subtract one the numbers two threw six would have to fit in to the multiples of seven subtracting one and five only fits in numbers that end with zero and its self, but two doesn’t fit into five so the number used would be with an zero (when one subtracted from seven’s multiple).
Part two: Process Now how do I figure this out? My idea concerning this problem is that it was somewhat difficult. The only method I did was take the number seven and multiply it by three. For all the others I subtracted the answer to three and saw some fit into the number. Then I didn’t know what to do next. So I called my dad to help me with this problem. He told me I should add ten to three to the multiply that by seven. So I did and it didn’t work until I stopped and used paper and pen to try and figure out the problem. I still couldn’t do it so I got my dad and we started over. So we took the number three and multiplied it by seven and we looked to see if two through six would fit in the answer when one was subtracted. When that didn’t work we started adding ten to the three. Eventually at the fourth time we added ten we got the answer for the problem! Part three: Solution So you now know how to figure it out,