How many bits of mask are required to provide 30 host addresses?
128 64 32 16 8 4 2 1 30 = 0 0 0 1 1 1 1 0 = 00011110
How many networks will be created using a 255.255.0.0 given a class A IP network (i.e., 10.0.0.0)? About 16,000,000
What would be the dotted decimal equivalent o the slash notation of /30? 11111111.11111111.11111111.11111100 255. 255. 255. 252 = 255.255.255.252
What would be the dotted decimal equivalent o the slash notation of /8? 11111111.0.0.0 255.0.0.0
What would be the dotted decimal equivalent o the slash notation of /17? 11111111.11111111.1000000.0 255. 255. 128.0 = 255.255.128.0
What would be the dotted decimal equivalent o the slash notation of /12? 11111111.11110000.0.0 255. 240.0.0 = 255.240.0.0
Given 9 bits of mask for the host portion, how many host addresses are available? 2^9 = 512 host addresses
Given 13 bits of mask for the host portion, how many host addresses are available? 2^13 = 8192 host addresses
Given 3 bits of mask for the host portion, how many host addresses are available? 2^3 = 8 host addresses
Given 8 bits of mask for the network portion, how many subnets are available? 2^8 = 256 host addresses
Given 4 bits of mask for the network portion, how many subnets are available? 2^4 = 16 host addresses
Explain the reasoning behind the concept of “subnet zero.” When looking for subnet zero, it'll help your figure out which is your interesting octet.
For a network address, what does the host portion of the address appear as in binary representation? For a broadcast