Hypotonic To Sheep's Red Blood Cells
In solution hypotonic to the sheep’s red blood cells, the red blood cells will lyse, as a result of the water entering the cell via osmosis.
First, a stock solution of NaCl was prepared at concentration 1.0M. Working solutions were made ranging from hypotonic to hypertonic with a negative control at isotonic solution (150mM). The solutions were diluted up to 4 mL into 5 test tubes, (0mM, 0.13mM, 0.15mM, 0.17mM, 0.3mM 0.5mM) using distilled water to dilute the stock solution. The working solutions were then added to 5 separate Eppendorf tubes at a volume of 0.9mL and the sheep’s blood was added at a volume of 0.3 mL, ensuring that the vial containing sheep’s blood was mixed gently to ensure even distribution of erythrocytes and plasma. Samples of the mixture (sheep’s blood in NaCl solution) were drawn using haematocrit tubes, ensuring that the blood does not exceed the blue marking, then sealed with wax using a wax plate. The haematocrit tubes were then centrifuged for 3 minutes at 10 000 rpms. The haematocrit tubes were then measured to obtain percent pack cell volume of the red blood cells in each solution. The results of the experiment confirm the hypothesis, as we can infer that the red blood cells lysed in the 0 mM solution, which would explain why no red blood cells were …show more content…
In 0mM solution no red blood cells are observed at the bottom of the haematocrit tube, the pack cell volume is 0%. At a concentration of 500 mM of NaCl the pack cell volume decreased from 7% (at the negative control) to 5%. The same trend is observed when comparing the results to another two sets of data, there is an increase in pack cell volume as NaCl concentration approached 150mM and then a decrease is observed as NaCl concentration continues to
First, a stock solution of NaCl was prepared at concentration 1.0M. Working solutions were made ranging from hypotonic to hypertonic with a negative control at isotonic solution (150mM). The solutions were diluted up to 4 mL into 5 test tubes, (0mM, 0.13mM, 0.15mM, 0.17mM, 0.3mM 0.5mM) using distilled water to dilute the stock solution. The working solutions were then added to 5 separate Eppendorf tubes at a volume of 0.9mL and the sheep’s blood was added at a volume of 0.3 mL, ensuring that the vial containing sheep’s blood was mixed gently to ensure even distribution of erythrocytes and plasma. Samples of the mixture (sheep’s blood in NaCl solution) were drawn using haematocrit tubes, ensuring that the blood does not exceed the blue marking, then sealed with wax using a wax plate. The haematocrit tubes were then centrifuged for 3 minutes at 10 000 rpms. The haematocrit tubes were then measured to obtain percent pack cell volume of the red blood cells in each solution. The results of the experiment confirm the hypothesis, as we can infer that the red blood cells lysed in the 0 mM solution, which would explain why no red blood cells were …show more content…
In 0mM solution no red blood cells are observed at the bottom of the haematocrit tube, the pack cell volume is 0%. At a concentration of 500 mM of NaCl the pack cell volume decreased from 7% (at the negative control) to 5%. The same trend is observed when comparing the results to another two sets of data, there is an increase in pack cell volume as NaCl concentration approached 150mM and then a decrease is observed as NaCl concentration continues to