1. Overall results and where they reasonable also exclude other results from each step
2. HCl was added to the unknown to form the precipitate. HCl was a good option because Cl is insoluble with lead and silver ions.
3. HCl is soluble in water. You add heat to break the bonds so that it can dissolve.
4. K2CrO4 was added in step 12 to see if a yellow precipitate was form. K2CrO4 was a good substance to use because it is insoluble