lab report
INTERPRETATION OF RESULTS:
This experiment circles around with the Newton’s second condition of equilibrium in rotational motion. It describes by net torque acting on a body which is zero. The ability of the body to rotate in a certain direction is varied according on how much torque is applied. To prove that, a beam that is subjected to two forces is balanced by adjusting the perpendicular distances. When applied force is weight, modification in masses added is also done. Once equilibrium is achieved, or when the beam is not moving at a horizontal position, we can calculate for the unknown forces applied through the utilization of this principle.
We balance the system given the ample forces acting on it. In general, application of Newton’s Second Condition of Equilibrium is applied here. By applying it, we could get the magnitude of one force acting on it, considering the other forces of known magnitudes. Thus, if weight is one of the forces, we could really get the mass of that specific object.
In the first part of the experiment, the first mass pan has 10 g weights on it while for the second, 5 g. By balancing, we measured a distance of 10 cm and 14 cm for each corresponding weight pans, P1 and P2. The weights added to pan 1 and pan2 affect the positions in the model balance if one contained a bigger mass compare to the other. Because they are not equal it will undergo to unstable state and also according to the definition of torque, applied forces multiplied by level arm. In balancing, I observed that the pan containing bigger mass will positioned closer to the axis of rotation while the pan containing smaller mass will positioned farther to the axis of rotation so that the amount of the torques that we may get in the two pans will be equal if equate them both. Also, when the beam is balance, the equilibrium is established, the weight and the perpendicular distance of the pan on the left side is directly proportional to the perpendicular distance of the
This experiment circles around with the Newton’s second condition of equilibrium in rotational motion. It describes by net torque acting on a body which is zero. The ability of the body to rotate in a certain direction is varied according on how much torque is applied. To prove that, a beam that is subjected to two forces is balanced by adjusting the perpendicular distances. When applied force is weight, modification in masses added is also done. Once equilibrium is achieved, or when the beam is not moving at a horizontal position, we can calculate for the unknown forces applied through the utilization of this principle.
We balance the system given the ample forces acting on it. In general, application of Newton’s Second Condition of Equilibrium is applied here. By applying it, we could get the magnitude of one force acting on it, considering the other forces of known magnitudes. Thus, if weight is one of the forces, we could really get the mass of that specific object.
In the first part of the experiment, the first mass pan has 10 g weights on it while for the second, 5 g. By balancing, we measured a distance of 10 cm and 14 cm for each corresponding weight pans, P1 and P2. The weights added to pan 1 and pan2 affect the positions in the model balance if one contained a bigger mass compare to the other. Because they are not equal it will undergo to unstable state and also according to the definition of torque, applied forces multiplied by level arm. In balancing, I observed that the pan containing bigger mass will positioned closer to the axis of rotation while the pan containing smaller mass will positioned farther to the axis of rotation so that the amount of the torques that we may get in the two pans will be equal if equate them both. Also, when the beam is balance, the equilibrium is established, the weight and the perpendicular distance of the pan on the left side is directly proportional to the perpendicular distance of the