Table 1:
CuSO4 xH2O before heating is blue colored, solid with small crystal like particles
While heating the blue color starts to fade
After heating it is completely white – color has faded – and particles are smaller due to the stirring
Calculations of Trial 1:
Molar Mass of H2O = 2 x (1.01) + 16.00 = 18.02gmol1-
How many moles of H2O evaporated Trial 1:
0.72g±0.04g/18.02gmol1- = 0.03995… ≈ 0.040mol±6.25% = 0.040mol±0.003mol
Molar Mass of CuSO4
Cu: 63.55 gmol1-
S=32.07 gmol1-
O x 4= (16.00) x 4=64.00 gmol1-
CuSO4= 159.62 gmol1-
Moles of anhydrous part (CuSO4)
1.35g±0.02g/159.62 gmol1-=0.0084575… ≈ 0.00846mol±1.48%=0.00846mol±0.00013mol
Moles of H2O in 1 mole of CuSO4
0.00846mol of CuSO4-----------> 0.040mol of H2O
1mol of CuSO4 ------------------> x mol of H2O
Uncertainties: 0.00013 x 100 / 0.00846=±1.5%
0.003 x 100 / 0.040 = 7.5... ≈ ±8% ---------------------> 1.5% + 8% = ±9.5% x= 0.040 x 1 / 0.00846 = 4.7281… ≈ 4.7mol±9.5% or 4.7mol±0.4mol
Calculations of Trial 2:
Molar Mass of H2O = 18.02gmol1-
How many moles of H2O evaporated Trial 2:
0.79g±0.04g/18.02gmol1- = 0.04384… ≈ 0.044mol±5.06% = 0.044mol±0.002mol
Molar Mass of CuSO4 = 159.62 gmol1-
Moles of anhydrous part (CuSO4)
1.43g±0.02g/159.62 gmol1-=0.008958… ≈ 0.00896mol±1.39%=0.00896mol±0.00012mol
Moles of H2O in 1 mole of CuSO4
0.00896mol of CuSO4-----------> 0.044mol of H2O
1mol of CuSO4 ------------------> x mol of H2O
Uncertainties: 0.00012 x 100 / 0.00896=±1.3%
0.002 x 100 / 0.044 = 4.5... ≈ ±5% ---------------------> 1.3% + 5% = ±6.3% ≈ ±6% x= 0.044 x 1 / 0.00896 = 4.9107… ≈ 4.9mol±6% or 4.9mol±0.3mol
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