Preview

Lub Dub Sound in Heart

Good Essays
Open Document
Open Document
576 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Lub Dub Sound in Heart
In my lab experimentation, all of the parent generation, or flies I started with, were wild-type or mutant phenotypically, but their genotypes were unknown. However, after I mated these flies and they produced offspring, the parental genotypes could be hypothesized based on phenotypic observations and ratios of the F1 and F2 generations. I then could check my observations by testing it using the Chi squared (X2) test.

A. Miniature Wings – (Sex-Linked Recessive)
To determine the inheritance of miniature wings I first crossed a female wild-type with a mutant male. The F1 generation results were 609(WT) females; 596(wild-type) males. 1:0 ratio of wild-type to mutants. The F2 generation results were as followed: females- 618(wild-type) ; Males – 288(wild-type) and 313 (mutant). 3:1 ratio of wild-type to mutant.
The reciprocal cross F1 generation produced 585(wild-type) females; 607(mutant) males. This suggests a 1:1 ratio and emphasis a sex-linked trait. The F2 generation confirms this hypothesis with a 1:1:1:1 ratio. The F2 generation results were as followed: Females- 291(Mutant) and 296(wild-type) ; Males- 321(mutant), 310(wild-type). Chi squared test results was 0.0296. I conclude miniature wings was x-linked recessive trait.

B. Eyeless – (Autosomal Recessive)
I first crossed a female mutant with a male wild-type. The F1 generation were all wild-type in a 1:0 ratio. The F2 generation produced a 3:1 ratio of wild-type to mutant with sex not being a factor.
The reciprocal cross produced all wild-types in a 1:1 ratio to male wild-type to female wild-type. The F2 generation, again, had a 1:1 ratio of male to female, but a 3:1 segregation of expression of the trait. The pattern between the crosses suggests the trait is autosomal recessive with no difference between the sexes. Chi square was 0.07862.

C. Bar Eyes – (Sex-linked Dominant)
Initially crossing a wild-type female to a mutant male with bar eyes, the F1 generation produced half (569)-mutant

You May Also Find These Documents Helpful

  • Good Essays

    The F1 wild-type female had a heterozygous eye color allele. This is why she had offspring of different types.…

    • 513 Words
    • 2 Pages
    Good Essays
  • Good Essays

    Kumabjara of Namjbar

    • 667 Words
    • 3 Pages

    c. Write out the genotypes of the F1 dragons that will be used to breed and give rise to the F2…

    • 667 Words
    • 3 Pages
    Good Essays
  • Good Essays

    In addition to wild-type flies, 29 different mutations of the common fruit fly, Drosophila melanogaster, are included in FlyLab. The 29 mutations are actual known mutations in Drosophila. These mutations create phenotypic changes in bristle shape, body color, antennae shape, eye color, eye shape, wing size, wing shape, wing vein structure, and wing angle. For the purposes of the simulation, genetic inheritance in FlyLab follows Mendelian principles of complete dominance. Examples of incomplete dominance are not demonstrated with this simulation. A table of the mutant phenotypes available in FlyLab can be viewed by clicking on the Genetic Abbreviations tab which appears at the top of the FlyLab homepage. When you select a particular phenotype, you are not provided with any information about the dominance or recessiveness of each mutation. FlyLab will select a fly that is homozygous for the particular mutation that you choose, unless a mutation is lethal in the homozygous condition in which case the fly chosen will be heterozygous. Two of your challenges will be to determine the zygosity of each fly in your cross and to determine the effects of each allele by analyzing the offspring from your…

    • 862 Words
    • 4 Pages
    Good Essays
  • Satisfactory Essays

    25.) When Thomas Hunt Morgan crossed his red-eyed F1 generation flies to each other, the F2 generation included both red and white-eyed flies. Remarkably, all the white-eyed flies were male. What was the explanation for this result?…

    • 495 Words
    • 1 Page
    Satisfactory Essays
  • Satisfactory Essays

    of different phenotypes would be a blend of the parental types and variation would be lost…

    • 1857 Words
    • 9 Pages
    Satisfactory Essays
  • Better Essays

    Genes are traits that give living things their own certain characteristic. Genes are inherited from the P generation to the F1 generation. As genes are passed down, they are given traits that are either contain all dominant genes known as homozygous dominant, or both dominant and recessive also known as heterozygous and last is homozygous recessive, meaning that the genes are both recessive. Dominant alleles are always present even if they also contain one recessive and the only way to express the recessive trait, both alleles must be recessive for the trait to be expressed. During sexual reproduction, 2 parents with different traits are crossbreed, which encourage cultural diversity out of the population. The offspring of the P1 generation is also call the hybrid since they have a mixed of traits from both parents. There are 2 type of crossbreeding first is…

    • 2413 Words
    • 10 Pages
    Better Essays
  • Better Essays

    Nt1310 Lab 6.2

    • 1483 Words
    • 6 Pages

    1. What are the percents of genotypes you would expect in any cross between two heterozygous parents? Use the letters B and b in your answer. BB= 25% ; bb= 25% ; Bb= 50%…

    • 1483 Words
    • 6 Pages
    Better Essays
  • Satisfactory Essays

    Fly Lab Instructions

    • 688 Words
    • 3 Pages

    1.c. Based on what you know about the principles of Mendelian genetics, predict the phenotypic ratio that you would expect to see for the F1 offspring of this cross and describe the phenotype of each fly.…

    • 688 Words
    • 3 Pages
    Satisfactory Essays
  • Good Essays

    In the reciprocal cross, the behavioural phenotypes were isolated from one another while the wing veins were kept constant (in this case both wild type). When the wild type mellow female Drosophila and wild type hyper male Drosophila were crossed, all female offspring obtained a similar phenotype to that of the male parental while all the male offspring had phenotypical combinations similar to that of the female parent. This set of results shows that the mellow behavioral phenotype is a recessive x-linked gene carried by the female because the resulting male offspring showed the same characteristics to that of the female parent (received X – chromosome from female parent). On an additional note, there was a higher frequency of females in comparison to men; 121 and 105 respectively. In addition, the behavioral gene is sex -linked also because of the different resulting phenotypical ratio in comparison to the cross carried out in vial one.…

    • 771 Words
    • 4 Pages
    Good Essays
  • Good Essays

    Biology Final Study Guide

    • 869 Words
    • 4 Pages

    tall x het. tall **always 3/4 dominant, 1/4 recessive Dihybrid- 2 heterozygous traits x same 2 heterozygous traits ex. het. tall, het. green x het.…

    • 869 Words
    • 4 Pages
    Good Essays
  • Satisfactory Essays

    Paper

    • 377 Words
    • 2 Pages

    4) What is the genotypic and phenotypic ratio from the F2 of a monohybrid cross?…

    • 377 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    They thought Mendel’s hereditary determinants were on a locus. They found out that the physical separation of alleles during anaphase I of meiosis accounts for Mendel’s principle of segregation. If the alleles for different genes are located on different chromosomes, they assort independently from one another in meiosis I. This confirmed the principle of independent assortment. Later on, the two scientists came up with the chromosome theory of inheritance, which states that independent assortment happens in metaphase and anaphase of meiosis I. To test the theory of inheritance, scientist Thomas Hunt Morgan used the fruit fly. At one point, Morgan noticed that a male fruit fly had white eyes rather than the wild type red eyes. He concluded that the white eyes resulted from a mutation. He mated a red-eyed female with a mutant white-eyed male and the results showed that all of the F_1 females had red eyes, but the F_1 males had white eyes. This was very peculiar because Mendel already proved that traits are not sex based. Morgan realized that the X chromosome in males and females explained his results. He determined that eye color is carried on the X chromosome and not on the Y chromosome. This is described as sex-linked inheritance. According to the X-linkage hypothesis, a female has two copies of the eye color gene because they have the two X chromosomes, whereas the male fruit flies have the one X chromosome that codes for eye color. The reciprocal cross of pea plants happened on non-sex chromosomes called autosomes. Genes on non-sex chromosomes show autosomal inheritance. Biologists now know that Boveri’s and Sutton's chromosome theory of inheritance was…

    • 600 Words
    • 3 Pages
    Good Essays
  • Better Essays

    Fruit Fly Lab Report

    • 1348 Words
    • 6 Pages

    Looking at all of the fruit flies, there is no possible way for the parent flies to be homozygous. If the parent flies were homozygous, both the F1 and the F2 phenotypes would be the same holding a 1:1ratio, instead of the 9:3:3:1 ratio that was observed. The purpose of this experiment was to determine the F1 genotype of fruit fly traits using the phenotypic ratio of the F2 generation and to express these results of the unknown cross through a Chi-square model. After taking data with the Chi-squared value of 5.64, the degrees of freedom were 3 and the p-value was between .05 and .2, it is confident to fail to reject the null hypothesis, which leads the experimenters to believe that the observed phenotypic ratio does significantly deviate from that expected under the assumption of Mendelian inheritance. In the future, exploring more complex animals other than fruit flies, such as mammals or reptiles, would make this experiment a little more difficult, but more interesting as well. Without Mendelian genetics, it would be much more difficult to predict traits in organisms across the living…

    • 1348 Words
    • 6 Pages
    Better Essays
  • Better Essays

    Aim: to establish whether characteristics produced from the offspring of a drosophila cross are recessive or dominant traits.…

    • 2429 Words
    • 10 Pages
    Better Essays
  • Good Essays

    genetics notes

    • 398 Words
    • 2 Pages

    The influence of nonrandom mating on the distribution of genotypes among a group of animals.…

    • 398 Words
    • 2 Pages
    Good Essays

Related Topics