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Nt1320 Unit 4

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Nt1320 Unit 4
Since the flux is sinusoidal, r.m.s = (form factor*average e.m.f )/turns But form factor = (r.m.s value)/(average value) =1.11, Then r.m.s value of E.m.f = 1.11*4F*max.Flux = 4.44F*max.Flux, But max .flux = B_m*A r.m.s value of E.m .f in primary turn (Tp) = 4.44F*B_m*A*T_p NOTE: Bm is assumed to be 15000Wb/m. F = Frequency of A.C input/ Output F=50 Hz By introducing stacking factor (10-8) and Tp factor (0.9) then we have Number of turns per volt = N_T/V =7/A =7/3.75=1.87turns/volts
The power Rating for the Inverter transformer (KVA) = 2.0KVA, E2= 24V Assuming the efficiency of transformer= 85%:
Then Input rating =output/Efficiency= 2000VA/0.85=2353VA …………..equation 17
I_p=P_1/V_P VP = 280V …………..equation 18
I_P=2353/280=8.4A
…show more content…
I_S=P_O/V_S Vs = 24V …………..equation 19
I_S=2000/24=83.3A
For practical design of inverter transformer Number of turns per volt for both primary and secondary winding is given by;
N_T/V= 7/A …………..equation

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