To calculate this, the outside air temperature at 5,000 feet must be converted to Rankin from Fahrenheit. Therefore, 52°F+460=512°R. Within the equation is non-standard pressure at 5,000 feet MSL (1,760.63 psf), symbolized by P, divided by the gas constant (1716(ft^2)/(S^2×°R)), symbolized by IR multiplied by the outside air temperature (512°R). When calculated the density (ρ) at 5,000 feet MSL is .00200 sl/(ft^3
To calculate this, the outside air temperature at 5,000 feet must be converted to Rankin from Fahrenheit. Therefore, 52°F+460=512°R. Within the equation is non-standard pressure at 5,000 feet MSL (1,760.63 psf), symbolized by P, divided by the gas constant (1716(ft^2)/(S^2×°R)), symbolized by IR multiplied by the outside air temperature (512°R). When calculated the density (ρ) at 5,000 feet MSL is .00200 sl/(ft^3