Prob and Stats M1A3
Raw Numeric Questionnaire Data
Question 1 2 3 4 5 6 7 8 9
Male 4 4.6 3.2 3.9 4.2 3.7 4.1 4.5 3.5
Female 4.2 4.1 4.2 4.6 3.9 4.1 4.7 4.1 4.2
Raw Numeric Questionnaire Data
Question 10 11 12 13 14 15 16 17 18
Male 4 3.9 4 3 4.5 4.9 3 3.3 3
Female 4 4.2 4.1 4 4.5 4.3 3.9 4 3.7 1)
Answer
Males numeric unites (E X) = 69.3
Males Questions (n) = 18
Mean = 69.3/18 = 3.85
Female numeric unites (E X) = 74.8
Female Questions (n) = 18
Mean of female manager = 74.8/18 = 4.16
Conclusion female managers have a higher mean than male managers but no other conclusion can come from the mean.
Data from the males 4, 4.6, 3.2, 3.9, 4.2, 3.7, 4.1, 4.5, 3.5, 4, 3.9, 4, 3, 4.5, 4.9, 3, 3.3, 3 Ordered Values – 3, 3, 3, 3.2, 3.3, 3.5, 3.7, 3.9, 3.9, 4, 4, 4, 4.1, 4.2, 4.5, 4.5, 4.6, 4.9 Median – 3.95
Data from the females 4.2, 4.1, 4.2, 4.6, 3.9, 4.1, 4.7, 4.1, 4.2, 4, 4.2, 4.1, 4, 4.5, 4.3, 3.9, 4, 3.7 Ordered Values – 3.7, 3.9, 3.9, 4, 4, 4, 4.1, 4.1, 4.1, 4.1, 4.2, 4.2, 4.2, 4.2, 4.3, 4.5, 4.6, 4.7 Median = 4.1
As the median values differ the conclusion is that the females have a higher median as compared to the males.
The mode for the data from
Males 4, 4.6, 3.2, 3.9, 4.2, 3.7, 4.1, 4.5, 3.5, 4, 3.9, 4, 3, 4.5, 4.9, 3, 3.3, 3
Mode = 4
Females 4.2, 4.1, 4.2, 4.6, 3.9, 4.1, 4.7, 4.1, 4.2, 4, 4.2, 4.1, 4, 4.5, 4.3, 3.9, 4, 3.7
Mode = 4.1 & 4.2
Variability
Xbar –x = 4.16 – 3.85 =0.31
Standard Deviation
Males Mean Deviation Deviation Squared Females Mean Deviation Deviation Squared
4 3.85 0.15 0.0225 4.2 4.16 0.04 0.0016
4.6 3.85 0.75 0.5625 4.1 4.16 -0.06 0.0036
3.2 3.85 -0.65 0.4225 4.2 4.16 0.04 0.0016
3.9 3.85 0.05 0.0025 4.6 4.16 0.44 0.1936
4.2 3.85 0.35 0.1225 3.9 4.16 -0.26 0.0676
3.7 3.85 -0.15 0.0225 4.1 4.16 -0.06 0.0036
4.1 3.85 0.25 0.0625 4.7 4.16 0.54 0.2916
4.5 3.85 0.65 0.4225 4.1 4.16 -0.06 0.0036 3.85 -0.35 0.1225 4.2 4.16 0.04 0.0016
4 3.85 0.15 0.0225 4 4.16 -0.16
Question 1 2 3 4 5 6 7 8 9
Male 4 4.6 3.2 3.9 4.2 3.7 4.1 4.5 3.5
Female 4.2 4.1 4.2 4.6 3.9 4.1 4.7 4.1 4.2
Raw Numeric Questionnaire Data
Question 10 11 12 13 14 15 16 17 18
Male 4 3.9 4 3 4.5 4.9 3 3.3 3
Female 4 4.2 4.1 4 4.5 4.3 3.9 4 3.7 1)
Answer
Males numeric unites (E X) = 69.3
Males Questions (n) = 18
Mean = 69.3/18 = 3.85
Female numeric unites (E X) = 74.8
Female Questions (n) = 18
Mean of female manager = 74.8/18 = 4.16
Conclusion female managers have a higher mean than male managers but no other conclusion can come from the mean.
Data from the males 4, 4.6, 3.2, 3.9, 4.2, 3.7, 4.1, 4.5, 3.5, 4, 3.9, 4, 3, 4.5, 4.9, 3, 3.3, 3 Ordered Values – 3, 3, 3, 3.2, 3.3, 3.5, 3.7, 3.9, 3.9, 4, 4, 4, 4.1, 4.2, 4.5, 4.5, 4.6, 4.9 Median – 3.95
Data from the females 4.2, 4.1, 4.2, 4.6, 3.9, 4.1, 4.7, 4.1, 4.2, 4, 4.2, 4.1, 4, 4.5, 4.3, 3.9, 4, 3.7 Ordered Values – 3.7, 3.9, 3.9, 4, 4, 4, 4.1, 4.1, 4.1, 4.1, 4.2, 4.2, 4.2, 4.2, 4.3, 4.5, 4.6, 4.7 Median = 4.1
As the median values differ the conclusion is that the females have a higher median as compared to the males.
The mode for the data from
Males 4, 4.6, 3.2, 3.9, 4.2, 3.7, 4.1, 4.5, 3.5, 4, 3.9, 4, 3, 4.5, 4.9, 3, 3.3, 3
Mode = 4
Females 4.2, 4.1, 4.2, 4.6, 3.9, 4.1, 4.7, 4.1, 4.2, 4, 4.2, 4.1, 4, 4.5, 4.3, 3.9, 4, 3.7
Mode = 4.1 & 4.2
Variability
Xbar –x = 4.16 – 3.85 =0.31
Standard Deviation
Males Mean Deviation Deviation Squared Females Mean Deviation Deviation Squared
4 3.85 0.15 0.0225 4.2 4.16 0.04 0.0016
4.6 3.85 0.75 0.5625 4.1 4.16 -0.06 0.0036
3.2 3.85 -0.65 0.4225 4.2 4.16 0.04 0.0016
3.9 3.85 0.05 0.0025 4.6 4.16 0.44 0.1936
4.2 3.85 0.35 0.1225 3.9 4.16 -0.26 0.0676
3.7 3.85 -0.15 0.0225 4.1 4.16 -0.06 0.0036
4.1 3.85 0.25 0.0625 4.7 4.16 0.54 0.2916
4.5 3.85 0.65 0.4225 4.1 4.16 -0.06 0.0036 3.85 -0.35 0.1225 4.2 4.16 0.04 0.0016
4 3.85 0.15 0.0225 4 4.16 -0.16