For these equations to be equivalent there is one condition you must put on any real number a. The condition that must be put on a is that a cannot be 0. The main reason that a cannot be 0 is because when we substitute 0 for a in the second equation you must multiply x times 0. X times 0 is 0. Then when you put 0 in for a on the other side of the equation you must multiply 0 and 2. 0 times 2 also equals 0. So, you get a solution set of {0}. When you compare that to the first solution set it is not the same. The first solution set is {2}. A solution set of {0} is different from a solution set of {2} making the two equations not equivalent. So a can be any real non-zero number. A can be any real non-zero number because of the multiplicative property of equality. That property states that if you multiply both sides of the equation by an integer they will stay
For these equations to be equivalent there is one condition you must put on any real number a. The condition that must be put on a is that a cannot be 0. The main reason that a cannot be 0 is because when we substitute 0 for a in the second equation you must multiply x times 0. X times 0 is 0. Then when you put 0 in for a on the other side of the equation you must multiply 0 and 2. 0 times 2 also equals 0. So, you get a solution set of {0}. When you compare that to the first solution set it is not the same. The first solution set is {2}. A solution set of {0} is different from a solution set of {2} making the two equations not equivalent. So a can be any real non-zero number. A can be any real non-zero number because of the multiplicative property of equality. That property states that if you multiply both sides of the equation by an integer they will stay