Question 1 of 12
The equilibrium constant Kp for the reaction CO(g) + Cl2(g) ↔ COCl2(g) is 5.62 x 1035 at 25°C. Calculate ΔGf° for COCl2 at 25°C. (ΔGf° for CO(g) = –137.3 kJ/mol at 25°C) PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_12_0\" VALUE=\"3\" DISABLED>" MACROBUTTON HTMLDirect A. –66.7 kJ/mol PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_12_0\" VALUE=\"1\" DISABLED>" MACROBUTTON HTMLDirect B. 188 kJ/mol PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_12_0\" VALUE=\"4\" DISABLED>" MACROBUTTON HTMLDirect C. 274.6 kJ/mol PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_12_0\" VALUE=\"2\" DISABLED>" MACROBUTTON HTMLDirect D. –160 kJ/mol PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_12_0\" VALUE=\"0\" CHECKED DISABLED>" MACROBUTTON HTMLDirect E. –341 kJ/mol
Question 2 of 12
Would you predict that the following reaction would proceed to an appreciable extent at 25°C?
MnO2(s) + 4H+(aq) + 2Cl‒(aq) → Mn2+(aq) + Cl2(g) + 2H2O(l)
(ΔH°f values (kJ/mol): MnO2(s), ‒520; Cl‒(aq), ‒167; Mn2+(aq), ‒221; H2O(l), ‒286)
(S° values (J/mol•K): MnO2(s), +53; Cl‒(aq), +57; Mn2+(aq), ‒74; Cl2(g), +223; H2O(l), +70) PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_19_0\" VALUE=\"0\" DISABLED>" MACROBUTTON HTMLDirect A. no because ΔG° is positive and Keq < 1 PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_19_0\" VALUE=\"3\" DISABLED>" MACROBUTTON HTMLDirect B. yes because ΔG° is negative and Keq > 1 PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_19_0\" VALUE=\"2\" DISABLED>" MACROBUTTON HTMLDirect C. yes because ΔG° is positive and Keq > 1 PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_19_0\" VALUE=\"1\" CHECKED DISABLED>" MACROBUTTON HTMLDirect D. no because ΔG° is negative and Keq < 1 PRIVATE "<INPUT TYPE=\"radio\" NAME=\"null_19_0\" VALUE=\"4\" DISABLED>" MACROBUTTON HTMLDirect E. yes because ΔG° is negative and Keq < 1