Quiz on Television Technology
2-12 what is the fraction of the total refresh time per frame spent in retrace of the electron beam for a noninterlaced raster system with a resolution of 1280 by 1024, a refresh rate of 60 Hz, a horizontal retrace time of 5 microseconds, and a vertical retrace time of 500 microseconds?
1sec = 10^6 usec
Refresh rate = 60Hz = 1/60 sec to scan = 16.7 msec
The time for horizontal retrace = 1024 x 5 usec
The time for vertical retrace = 500 usec
Total time spent for retrace = 5120 + 500 = 5620 usec = 5.62 msec
The fraction of the total refresh time frame spent in retrace = 5.62 / 16.7 = 0.337
2-13 Assuming that a certain full-color (24-bit per pixel) RGB raster system has a 512-by-512 frame buffer, how many distinct color choices (intensity levels) would we have available? How many different colors could we display at any one time?
Total number of distinct color available is 224
Total number of colors we could display at one time is 512 x 512
2 Assuming that a certain RGB raster system has 512*512 frame buffer with 12 bit per pixel and color lookup table with 24 bit for each entry
1 How many distinct color choice we have available
2 How many different color could we display at any one time?
3 How much storage spent altogether for the frame buffer and the color lookup table?
Total number of distinct color available is 224
Total number of different color could display at any one time is 212
The storage spent for frame buffer is 512 X 512 X 12 bit = 3145728 bit
The storage spent for the color lookup table is 212 X 24 bit = 98304 bit
So the total storage spent altogether is 3145728 + 98304 = 3244032 bit
2-12 what is the fraction of the total refresh time per frame spent in retrace of the electron beam for a noninterlaced raster system with a resolution of 1280 by 1024, a refresh rate of 60 Hz, a horizontal retrace time of 5 microseconds, and a vertical retrace time of 500 microseconds?
1sec = 10^6 usec
Refresh rate = 60Hz = 1/60 sec to
1sec = 10^6 usec
Refresh rate = 60Hz = 1/60 sec to scan = 16.7 msec
The time for horizontal retrace = 1024 x 5 usec
The time for vertical retrace = 500 usec
Total time spent for retrace = 5120 + 500 = 5620 usec = 5.62 msec
The fraction of the total refresh time frame spent in retrace = 5.62 / 16.7 = 0.337
2-13 Assuming that a certain full-color (24-bit per pixel) RGB raster system has a 512-by-512 frame buffer, how many distinct color choices (intensity levels) would we have available? How many different colors could we display at any one time?
Total number of distinct color available is 224
Total number of colors we could display at one time is 512 x 512
2 Assuming that a certain RGB raster system has 512*512 frame buffer with 12 bit per pixel and color lookup table with 24 bit for each entry
1 How many distinct color choice we have available
2 How many different color could we display at any one time?
3 How much storage spent altogether for the frame buffer and the color lookup table?
Total number of distinct color available is 224
Total number of different color could display at any one time is 212
The storage spent for frame buffer is 512 X 512 X 12 bit = 3145728 bit
The storage spent for the color lookup table is 212 X 24 bit = 98304 bit
So the total storage spent altogether is 3145728 + 98304 = 3244032 bit
2-12 what is the fraction of the total refresh time per frame spent in retrace of the electron beam for a noninterlaced raster system with a resolution of 1280 by 1024, a refresh rate of 60 Hz, a horizontal retrace time of 5 microseconds, and a vertical retrace time of 500 microseconds?
1sec = 10^6 usec
Refresh rate = 60Hz = 1/60 sec to