student workers

RUNNING HEAD: ASSIGNMENT

Week Three Written Assignment
Jessica Sanchez
MAT126: Survey of Mathematical Methods
Instructor: Lotlamoreng Mosiane
February 9, 2012

ASSIGNMENT 2 PROJECT 1 For project #1 we are to solve equations (a) and (c) using all 6 steps listed in the example. The basis of this project actually comes from an interesting method for solving quadratic equations.
This method originated from India. Below is the list for the step by step instructions I used from the method derived in India to solve equations (a) : x2-2x-13=0 and (c) : x2+12x-64=0
1. Move the constant term to the right side of the equation.
2. Multiply each term in the equation by four times the coefficient of the x squared term.
3. Square the coefficient of the original x term and add it to both sides of the equation.
4. Take the square root of both sides.
5. Set the left side of the equation equal to the positive square root of the number on the right side and solve for x.
6. Set the left side of the equation equal to the negative root of the number on the right side of the equation and solve for x.
Equation (a)
Step 1: Move the constant term to the right side of the equation.
X2-2x-13=0
X2-2x-13+13=0+13
X2-2x+0=0+13
X2-2x=0+13
X2-2x=13
Step 2: Multiply each term in the equation by four times the coefficient of the x squared term.
The coefficient of the x2 term is 1.
X2-2x=13
(4*1)*(x2-2x=13)
ASSIGNMENT 3

(4)*(X2-2X=13)
(4)*X2+(4)*(-2X)=(4)*(13)
4X2-8X=52
Step 3: Square the coefficient of the original x term and add it to both sides of the equation.
The coefficient of the original x term is -2.