Surface Area And Volume Lab Report
In Parts A and C, the relationship between surface area and volume was investigated. Plasticine was formed into a cube and a sphere; both shapes were cut in half. It was found that plasticine volume should not vary, two halves have a greater surface area than a whole, and cubes have a greater surface area than spheres of the same volume. In Part B, the relationship between diffusion and surface area to volume ratio was investigated. Three agar-phenolphthalein-sodium hydroxide cubes of different sizes were exposed to a sulfuric acid solution. It was found that the cube with the smallest volume had the highest rate of diffusion. It was concluded that since life-preserving diffusion is more efficient for small cells, size influences growth and
…show more content…
The dimensions of the prisms were measured and recorded, and their combined surface area, volume, and surface area to volume ratio were calculated.
1. Three cubes of agar-phenolphthalein-sodium hydroxide were cut, with one having approximate dimensions of 1cm x 1cm x 1cm, another 2cm x 2cm x 2cm, and the other 3cm x 3cm x 3cm.
2. The exact dimensions of each cube were measured and recorded and its volume was calculated.
3. Each cube was submerged in a 0.1M sulfuric acid solution in separate beakers for ten minutes; they were then dried through blotting with a paper towel.
4. Each cube was cut in half, forming two equal rectangular prisms. Two dimensions of the coloured portion of the cube were measured and recorded.
5. A prism from each cube was then cut in half. The final dimension of the coloured portion of the cube was measured and recorded.
6. Using the measured dimensions, the volume of the coloured portion of the cube was calculated.
7. The volume of the uncoloured portion of the cube was calculated by subtracting the total volume of the cube by the volume of the coloured portion of the cube.
8. The percentage by volume of the uncoloured portion of the cube was calculated by dividing the volume of the uncoloured portion of the cube by the total volume of the cube and multiplying by
The dimensions of the prisms were measured and recorded, and their combined surface area, volume, and surface area to volume ratio were calculated.
1. Three cubes of agar-phenolphthalein-sodium hydroxide were cut, with one having approximate dimensions of 1cm x 1cm x 1cm, another 2cm x 2cm x 2cm, and the other 3cm x 3cm x 3cm.
2. The exact dimensions of each cube were measured and recorded and its volume was calculated.
3. Each cube was submerged in a 0.1M sulfuric acid solution in separate beakers for ten minutes; they were then dried through blotting with a paper towel.
4. Each cube was cut in half, forming two equal rectangular prisms. Two dimensions of the coloured portion of the cube were measured and recorded.
5. A prism from each cube was then cut in half. The final dimension of the coloured portion of the cube was measured and recorded.
6. Using the measured dimensions, the volume of the coloured portion of the cube was calculated.
7. The volume of the uncoloured portion of the cube was calculated by subtracting the total volume of the cube by the volume of the coloured portion of the cube.
8. The percentage by volume of the uncoloured portion of the cube was calculated by dividing the volume of the uncoloured portion of the cube by the total volume of the cube and multiplying by