Answer
7. The Taguchi Loss Function for PlataLimpia, Inc. part is: L(x) = k (x - T)2
$15 = k (0.025)2 k = 24000
L(x) = k (x - T)2 = 24000 (x - T)2
8. A team was formed to study the dishwasher part at PlataLimpia, Inc. described in Problem 7. While continuing to work to find the root cause of scrap, they found a way to reduce the scrap cost to $10 per part. a. Determine the Taguchi loss function for this situation. b. If the process deviation from target can be held at 0.015 cm, what is the Taguchi loss?
Answer
8. The Taguchi Loss Function is: L(x) = k (x - T)2
a) $10 = k (0.025)2 k = 16000
L(x) = k (x - T)2 = 16000 (x - T)2
b) L(x) = 16000 (x - T)2
L(0.015) = 16000 (0.015)2 = $3.60
9. A specification for the length of an auto part at PartsDimensions, Inc. is 5.0 ± 0.10 centimeters (cm). It costs $50 to scrap a part that is outside the specifications. Determine the Taguchi loss function for this situation.
Answer
9. The Taguchi Loss Function is: L(x) = k (x - T)2
$50 = k (0.10)2 k = 5000
L(x) = k (x - T)2 = 5000 (x - T)2
10. A team was formed to study the auto part at PartsDimensions described in Problem 9. While continuing to work to find the root cause of scrap, the team found a way to reduce the scrap cost to $30 per part. a. Determine the Taguchi loss function for this situation. b. If the process deviation from target can be held at 0.020 cm, what is the Taguchi loss?
Answer
10. The Taguchi Loss Function is: L(x) = k (x - T)2
a) $30 = k (0.10)2 k = 3000
L(x) = k (x - T)2 = 3000 (x - T)2 b) L(x) = 3000 (x - T)2
L(0.020) = 3000 (0.020)2 = $ 1.20
11. Ruido Unlimited makes