The three graphs were plotted using data collected during the experiment, Figure 1, 2 and 3 Figure 1
Figure 2
Figure 3
2. Determine the proportional limit of the test specimen:
Proportional limits are approximately as follows- * copper is 8,888 psi * Aluminum is 6,666 psi * Polyester is 9,696 psi
3. Determine the Elastic Modulus of the specimens: * The Modulus of Elasticity for copper specimen is 16,687 ksi., figure 4. * The Modulus of Elasticity for Aluminum specimen is 89,991 ksi, figure 5. * The Modulus of Elasticity for Polyester specimen is 136,532 ksi, figure 6. Figure 4 Figure 5 Figure 6
4. Determine the Modulus of resilience and toughness of samples: * Copper: resilience=2304.30 psi, toughness=73468.13 in*ib/in^3 * Aluminum: resilience= 987.53 psi, toughness =5360.80in*ib/in^3 * Polyester: resilience=125.69 psi, toughness =12353.05 in*lb/in^3
*The resilience was calculated using 1/2b*h at the point of proportional limit
*The toughness was approximated by using total area under curve and applying Riemann Sum
5. Determine Engineering Ultimate and Breaking Strength of the samples tested:
Copper UTS 22,222 & Breaking Strength 25,770 psi
Aluminum UTS 13,333 and Breaking Strength 18,933 psi
Polyester UTS 15,555 and Breaking Strength 20,266 psi
6. Percent Elongation at break: [Lf-lo/lo]*100
Copper =17%
Aluminum=4.44%
Polyester=18.76%
7. Compare published values including % differences and discuss the accuracy of the results: | MATERIAL TYPE | PUBLISHED | EXPERIMENTAL | Modulus Of Elasticity | Copper C110 | 16,700 ksi | 16,687 ksi | | Aluminum Alloy 1000 series | 6.96-107,00 ksi | 89,991 ksi | | Polyester (Thermoplastic) | .377-1920 ksi | 136,522 ksi | Tensile, Ultimate | Copper C110 | 36300 psi | 22,222 psi | | Aluminum Alloy 1000 series | 102-232,000 psi | 13,333 psi | |
References: MatWeb, Material Data Sheets