Week 4 Quiz
University of Phoenix Material
Week Four Quiz
1. WHICH OF THE FOLLOWING STATEMENTS ARE CORRECT?
a. A normal distribution is any distribution that is not unusual. (Correct)
b. The graph of a normal distribution is bell-shaped. (Correct)
c. If a population has a normal distribution, the mean and the median are not equal.
d. The graph of a normal distribution is symmetric. (Correct)
Using the 68-95-99.7 rule:
Assume that a set of test scores is normally distributed with a mean of 100 and a standard deviation of 20. Use the 68-95-99.7 rule to find the following quantities:
Suggest you make a drawing and label first…
a. Percentage of scores less than 100 50%
b. Relative frequency of scores less than 120 84%
c. Percentage of scores less than 140 97.5%
d. Percentage of scores less than 80 16%
e. Relative frequency of scores less than 60 2.5%
f. Percentage of scores greater than 120 16%
2. Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers).
a. If you have a body temperature of 99.00 °F, what is your percentile score?
(99-98.2)/0.62=1.29
In table 5-1, 1.29 corresponds to 90th percentile.
b. Convert 99.00 °F to a standard score (or a z-score).
1.29. (99 - 98.2) / 0.62 = 1.29
c. Is a body temperature of 99.00 °F unusual? Why or why not?
Not unusual. Follow the 68-95-99.7 rule, 99.00 °F is within two standard deviations of the mean (96.96 - 99.44°F)
d. Fifty adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 °F or lower?
(97.98 - 98.2) / 0.62 = - 0.35
In table 5-1, - 0.35 corresponds to 36%.
50 x 36% = 18
So a 36% or 18 adults are likelihood that the mean of
Week Four Quiz
1. WHICH OF THE FOLLOWING STATEMENTS ARE CORRECT?
a. A normal distribution is any distribution that is not unusual. (Correct)
b. The graph of a normal distribution is bell-shaped. (Correct)
c. If a population has a normal distribution, the mean and the median are not equal.
d. The graph of a normal distribution is symmetric. (Correct)
Using the 68-95-99.7 rule:
Assume that a set of test scores is normally distributed with a mean of 100 and a standard deviation of 20. Use the 68-95-99.7 rule to find the following quantities:
Suggest you make a drawing and label first…
a. Percentage of scores less than 100 50%
b. Relative frequency of scores less than 120 84%
c. Percentage of scores less than 140 97.5%
d. Percentage of scores less than 80 16%
e. Relative frequency of scores less than 60 2.5%
f. Percentage of scores greater than 120 16%
2. Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers).
a. If you have a body temperature of 99.00 °F, what is your percentile score?
(99-98.2)/0.62=1.29
In table 5-1, 1.29 corresponds to 90th percentile.
b. Convert 99.00 °F to a standard score (or a z-score).
1.29. (99 - 98.2) / 0.62 = 1.29
c. Is a body temperature of 99.00 °F unusual? Why or why not?
Not unusual. Follow the 68-95-99.7 rule, 99.00 °F is within two standard deviations of the mean (96.96 - 99.44°F)
d. Fifty adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 °F or lower?
(97.98 - 98.2) / 0.62 = - 0.35
In table 5-1, - 0.35 corresponds to 36%.
50 x 36% = 18
So a 36% or 18 adults are likelihood that the mean of