Preview

workbook 18

Satisfactory Essays
Open Document
Open Document
321 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
workbook 18
1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (–53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places. x=5.48, SD=22.93
5.48+1.96(22.93) = 170.5992
5.48-1.96(22.93)=80.7136
(80.71,170.60)

2. Which of the following values from Table 1 tells us about variability of the scores in a distribution?
c. 22.57

3. Assuming that the distribution for General Health Perceptions is normal, 95% of the females’ scores around the mean were between what values? Round your answer to two decimal places. x=39.71, SD=25.46
39.71+1.96(25.46) = 89.6116
39.71-1.96(25.46) = -10.1916
(-10.19, 89.61)

4. Assuming that the distribution of scores for Pain is normal, 95% of the men’s scores around the mean were between what two values? Round your answer to two decimal places. x=52.53, SD=30.90
52.53+1.96(30.90) = 113.094
52.53-1.96(30.90) = -8.034
(-8.03, 113.09)

5. Were the body image scores significantly different for women versus men? Provide a rationale for your answer.
Yes, body image scores were significantly higher for women (73.1 ± 17.0) than men (60.2 ± 17.0).

6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the men’s mental health scores around the mean in this distribution? Round your answer to two decimal places. x= 57.09, SD=23.72
57.09+2.58(23.72)= 118.2876
57.09-2.58(23.72)= -4.1076
(-4.11, 118.29)

7. Assuming that the distribution of scores for Physical Functioning in women is normal, where are 99% of the women’s scores around the mean in this distribution? Round your answer to two decimal places. X= 65.20, SD=29.79
65.20+2.58(29.79) = 142.0582
65.20-2.58(29.79) = -11.6582
(-11.66, 142.06)

8. Assuming that the distribution of scores is normal, 99% of HIV-positive body image scores around the mean were between what two values? Round your answer to

You May Also Find These Documents Helpful

  • Good Essays

    9. Assume that it takes a college student an average of 5 minutes to find a parking spot in the main parking lot. Assume also that this time is normally distributed with a standard deviation of 2 minutes. What time is exceeded by approximately 75% of the college students when trying to find a parking spot in the main parking lot?…

    • 850 Words
    • 3 Pages
    Good Essays
  • Good Essays

    QNT 561 Final Exam

    • 697 Words
    • 5 Pages

    11. We wish to develop a confidence interval for the population mean. The population follows the normal distribution, the standard deviation of the population is 3, and we have a sample of 10 observations. We decide to use the 90 percent level of confidence. The appropriate value of to represent the level of confidence is…

    • 697 Words
    • 5 Pages
    Good Essays
  • Good Essays

    Math300

    • 524 Words
    • 2 Pages

    With a mean score of 14.87, a standard deviation of 0.55033, and a desired confidence level of 95%, the corresponding confidence interval is + 0.2. There is a 95% certainty that the true population mean falls within the range of 14.67 to 15.07.…

    • 524 Words
    • 2 Pages
    Good Essays
  • Satisfactory Essays

    Exercise 20 HLT-362V

    • 471 Words
    • 2 Pages

    7. Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 471 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    HLT 362 Exercise 18

    • 352 Words
    • 2 Pages

    Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 352 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    1. Sally scores 1.5 on this test. How many standard deviations is Sally from the mean? (Show your calculations and answer in a complete sentence.)…

    • 455 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    week 2 quiz

    • 401 Words
    • 2 Pages

    2. Assume that a set of test scores is normally distributed with a mean of 100 and a standard…

    • 401 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Exer20

    • 494 Words
    • 2 Pages

    Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 494 Words
    • 2 Pages
    Good Essays
  • Powerful Essays

    St 101 Question Paper

    • 2716 Words
    • 11 Pages

    Important Note: While most of the questions on this sample exam are in a multiple choice format, the questions on the exam will for the most part be partial credit type questions where you must show some work to obtain full credit. 1. The heights of American men aged 18 to 24 can be described by a Normal model with mean 68 inches and standard deviation 2.5 inches. Half of all young men are shorter than a) 65.5 inches b) 68 inches c) 70.5 inches d) can't tell because the median height is not given Use the information in Problem 1 and the 68-95-99.7 rule to determine the percentage of young men that are taller than 6' 1". The grade point averages (GPA) of…

    • 2716 Words
    • 11 Pages
    Powerful Essays
  • Satisfactory Essays

    Exercise 20

    • 458 Words
    • 2 Pages

    7. Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 458 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Week 4 Quiz

    • 677 Words
    • 3 Pages

    Assume that a set of test scores is normally distributed with a mean of 100 and a standard deviation of 20. Use the 68-95-99.7 rule to find the following quantities:…

    • 677 Words
    • 3 Pages
    Good Essays
  • Satisfactory Essays

    Excersise 20b

    • 531 Words
    • 2 Pages

    68% of the values lie within 1 standard deviation of the mean. Therefore the interval is,…

    • 531 Words
    • 2 Pages
    Satisfactory Essays
  • Powerful Essays

    302 Mid Notes

    • 2019 Words
    • 9 Pages

    The worksheet “Insurance” in the Excel workbook MATH302_Midterm.xls, which is attached, contains data on the percentage of people without health insurance coverage. These data are based on samples taken in 2004 for the fifty states and the District of Columbia. Use these data to answer questions 1 and 2.a. On average, what percentage of the people in the fifty states and the District of Columbia do not have health insurance? Mean: 14.15 Round your answer to 2 decimal places as necessary.b. What is the median percentage of people in the fifty states and District of Columbia who do not have health insurance? Median: 13.50 Round your answer to 2 decimal places as necessary.c. What is the standard deviation of the percentage of people in the fifty states and District of Columbia who do not have health insurance?Standard deviation: 4.10 Round your answer to 2 decimal places as necessary. Answer Key: 14.15, 13.50, 3.96|4.16…

    • 2019 Words
    • 9 Pages
    Powerful Essays
  • Satisfactory Essays

    Module 3

    • 250 Words
    • 2 Pages

    7. Assuming that the distribution of scores for the postoperative CVLT Retrieval T scores is normal, the middle 68% of the patients had T scores between what two values?…

    • 250 Words
    • 2 Pages
    Satisfactory Essays
  • Satisfactory Essays

    Assignment

    • 293 Words
    • 2 Pages

    IQ is intended to be normally distributed with a mean of 100 and a standard deviation of 15…

    • 293 Words
    • 2 Pages
    Satisfactory Essays

Related Topics