yield

Yield of CuCl2.2DMSO
Formula weight (Mr) of CuCl2 = 63.55 + (35.45 x 2) =134.45g/mol
Formula weight of product CuCl2.2DMSO = 134.45 + 2[16 + 32.06 + (12.01 x 2) + (1.0079 x 6)] = 290.704g/mol

Mass of CuCl2= 0.850g
Equation for reaction
CuCl2 + 2DMSO -> CuCl22DMSO
Mole ratio between CuCl2 and CuCl22DMSO = 1:1
Mole of CuCl2 = Mass/ Mr = 0.850/134.45 = 0.00632 moles

Since the ratio between CuCl2 and CuCl22DMSO = 1:1, mole of CuCl2DMSO is also 0.0063 moles.
To find theoretical yield of CuCl2.2DMSO
Mass = Mr x mole
=290.704 x 0.00632
= 1.837g
The actual yield gained is 1.573g
The percentage yield = (actual yield/ thereotical yield) x 100%
= (1.573/1.837) x 100% = 85.63%

Reference: http://orgchem.colorado.edu/Technique/Procedures/Notebook/Yield.html

Yield of Cu(gly-)2.H2O ( Isomer 1)
Formula weight (Mr) of (CH3CO2)2Cu.H2O = [[12.01 + (1.0079 x 3) + 12.01 + (16 x 2)] x 2 ] + 63.55 + (1.0079 x2) + 16 = 199.65g/mol
Formula weight (Mr) of Cu(gly-)2.H2O = 63.55 + [[14.01 + (1.0079 x 2) + 12.01 + (1.0079 x 2) + 12.01 + (16 x 2)] x 2 ] + (1.0079 x 2 )] + 16 = 229.68g/mol

Mass of (CH3CO2)2Cu.H2O = 2.0g
Equation for reaction
(CH3CO2)2Cu.H2O + 2NH2CH2COOH  Cu(NH2CH2COO)2.H2O + 2CH3CO2H

Mole ratio between (CH3CO2)2Cu.H2O and Cu(NH2CH2COO)2.H2O is 1:1.
Mass of (CH3CO2)2Cu.H2O = 2.0g
Moles of (CH3CO2)2Cu.H2O = Mass / Mr = 2/199.65 = 0.01 moles
Since Mole ratio between (CH3CO2)2Cu.H2O and Cu(NH2CH2COO)2.H2O is 1:1, mole of Cu(NH2CH2COO)2.H2O = 0.01 mole
Theoretical yield of Cu(NH2CH2COO)2.H2O = Mr x mole = 229.68 x 0.01 = 2.296 g
Actual yield gain = 2.587g

Percentage of yield = (Actual yield/ Thereotical Yield) x 100% = (2.587/2.296) X 100% = 112.67%

Yield of Cu(gly-)2.H2O ( Isomer 2B and 2A )
Formula weight (Mr) of Cu(gly-)2.H2O = 63.55 + [[14.01 + (1.0079 x 2) + 12.01 + (1.0079 x 2) + 12.01 + (16 x 2)] x 2 ] + (1.0079 x 2 )] + 16 = 229.68g/mol
Mass of (CH3CO2)2Cu.H2O = 0.2g (method b)
Mass of (CH3CO2)2Cu.H2O